我有一个名为theGarage
的主类,其中包含我们的客户,供应商和工作类的实例。
我想将程序数据保存到XML文件中,我使用了下面的代码(只是一个片段,我有其他类的匹配代码)。我想知道是否有更简单的方法来执行此操作,例如将整个theGarage类写入XML文件并将其读入,而不必像下面那样编写所有这些代码。
public void saveToFile()
{
using (XmlWriter writer = XmlWriter.Create("theGarage.xml"))
{
writer.WriteStartDocument();
///
writer.WriteStartElement("theGarage");
writer.WriteStartElement("Customers");
foreach (Customer Customer in Program.theGarage.Customers)
{
writer.WriteStartElement("Customer");
writer.WriteElementString("FirstName", Customer.FirstName);
writer.WriteElementString("LastName", Customer.LastName);
writer.WriteElementString("Address1", Customer.Address1);
writer.WriteElementString("Address2", Customer.Address2);
writer.WriteElementString("Town", Customer.Town);
writer.WriteElementString("County", Customer.County);
writer.WriteElementString("PostCode", Customer.Postcode);
writer.WriteElementString("TelephoneHome", Customer.TelephoneHome);
writer.WriteElementString("TelephoneMob", Customer.TelephoneMob);
//begin vehicle list
writer.WriteStartElement("Vehicles");
foreach (Vehicle Vehicle in Customer.Cars)
{
writer.WriteStartElement("Vehicle");
writer.WriteElementString("Make", Vehicle.Make);
writer.WriteElementString("Model", Vehicle.Model);
writer.WriteElementString("Colour", Vehicle.Colour);
writer.WriteElementString("EngineSize", Vehicle.EngineSize);
writer.WriteElementString("Registration", Vehicle.Registration);
writer.WriteElementString("Year", Vehicle.YearOfFirstReg);
writer.WriteEndElement();
}
writer.WriteEndElement();
writer.WriteEndElement();
}
}
}
答案 0 :(得分:42)
有更简单的序列化对象的方法,请使用XmlSerializer
。请参阅文档here。
将您的车库序列化为文件的代码段可能如下所示:
var garage = new theGarage();
// TODO init your garage..
XmlSerializer xs = new XmlSerializer(typeof(theGarage));
TextWriter tw = new StreamWriter(@"c:\temp\garage.xml");
xs.Serialize(tw, garage);
从文件加载车库的代码:
using(var sr = new StreamReader(@"c:\temp\garage.xml"))
{
garage = (theGarage)xs.Deserialize(sr);
}
答案 1 :(得分:7)
如果有几个漂亮的扩展方法,那么你可以轻松地从/向文件读/写这个。
public static class Extensions
{
public static string ToXml(this object obj)
{
XmlSerializer s = new XmlSerializer(obj.GetType());
using (StringWriter writer = new StringWriter())
{
s.Serialize(writer, obj);
return writer.ToString();
}
}
public static T FromXml<T>(this string data)
{
XmlSerializer s = new XmlSerializer(typeof(T));
using (StringReader reader = new StringReader(data))
{
object obj = s.Deserialize(reader);
return (T)obj;
}
}
}
例如
var xmlData = myObject.ToXml();
var anotherObject = xmlData.FromXml<ObjectType>();
答案 2 :(得分:1)
我刚写了a blog post on saving an object's data to Binary, XML, or Json。以下是向/从XML写入和读取类实例的函数。有关详细信息,请参阅我的博文。
要求System.Xml程序集包含在项目中。
/// <summary>
/// Writes the given object instance to an XML file.
/// <para>Only Public properties and variables will be written to the file. These can be any type though, even other classes.</para>
/// <para>If there are public properties/variables that you do not want written to the file, decorate them with the [XmlIgnore] attribute.</para>
/// <para>Object type must have a parameterless constructor.</para>
/// </summary>
/// <typeparam name="T">The type of object being written to the file.</typeparam>
/// <param name="filePath">The file path to write the object instance to.</param>
/// <param name="objectToWrite">The object instance to write to the file.</param>
/// <param name="append">If false the file will be overwritten if it already exists. If true the contents will be appended to the file.</param>
public static void WriteToXmlFile<T>(string filePath, T objectToWrite, bool append = false) where T : new()
{
TextWriter writer = null;
try
{
var serializer = new XmlSerializer(typeof(T));
writer = new StreamWriter(filePath, append);
serializer.Serialize(writer, objectToWrite);
}
finally
{
if (writer != null)
writer.Close();
}
}
/// <summary>
/// Reads an object instance from an XML file.
/// <para>Object type must have a parameterless constructor.</para>
/// </summary>
/// <typeparam name="T">The type of object to read from the file.</typeparam>
/// <param name="filePath">The file path to read the object instance from.</param>
/// <returns>Returns a new instance of the object read from the XML file.</returns>
public static T ReadFromXmlFile<T>(string filePath) where T : new()
{
TextReader reader = null;
try
{
var serializer = new XmlSerializer(typeof(T));
reader = new StreamReader(filePath);
return (T)serializer.Deserialize(reader);
}
finally
{
if (reader != null)
reader.Close();
}
}
// Write the list of salesman objects to file.
WriteToXmlFile<Customer>("C:\TheGarage.txt", customer);
// Read the list of salesman objects from the file back into a variable.
Customer customer = ReadFromXmlFile<Customer>("C:\TheGarage.txt");
答案 3 :(得分:0)
对于我的项目,我使用DataContractSerializer。我与XmlSerializer形成对比,它可以处理对同一对象的多个引用,使得数据不会在xml中重复并恢复为已保存。