Question

我有一个像这样的文件路径列表：

FILE_PATH := a1.so a2.so bla/a3.so bla/a3.so bla/blo/a4.so....

我需要在basename中添加一个前缀才能得到：

FILE_PATH_PREFIX := liba1.so liba2.so bla/liba3.so bla/liba3.so bla/blo/liba4.so....

任何想法？

Answer 1

查看Make的addprefix函数。

这是我们使用addsuffix将obj文件放在下面一个目录的示例来源。

SOURCE += MainThread.cpp
SOURCE += Blah.cpp

OBJ=$(join $(addsuffix ../obj/, $(dir $(SOURCE))), $(notdir $(SOURCE:.cpp=.o)))

从制作手册： http://www.gnu.org/software/make/manual/make.html

$(addprefix prefix,names...)

The argument names is regarded as a series of names, separated by whitespace; 
prefix is used as a unit. The value of prefix is prepended to the front of each 
individual name and the resulting larger names are concatenated with single 
spaces between them. For example,

              $(addprefix src/,foo bar)

produces the result `src/foo src/bar'.

makefile：如何在basename中添加前缀？

1 个答案: