Question

我有一个关于如何在我的PHP代码中显示正确的表格布局的问题：

我想在表格中显示答案及其文字输入。现在，它显示如下：

QuestionNo   Question             Answer        Marks Per Answer     
1            What is 2+2          B             (text input)         
2            Name the 3 hobbits?  BCE           (text input)

我想更改表格的显示，使其如下所示：

 QuestionNo  Question             Answer        Marks Per Answer 
 1           What is 2+2?          B             (text input)
 2           Name the 3 Hobbits?   B             (text input)                   
                                   C             (text input)
                                   E             (text input)

正如您从新显示屏中看到的那样。我希望每个问题的每个答案都显示在他们自己的行中，而不是每个问题的所有答案都在一行中，这就是它正在做的事情。
我希望文本输入也显示在自己的行中，如答案：

我的问题是如何实现第1点和第2点以便它可以匹配新的布局？

以下是当前显示的代码：

  <?php  
    $assessment = $_SESSION['id'] . $sessionConcat;
    include('connect.php');

    $query = "SELECT q.SessionId, s.SessionName, q.QuestionId, q.QuestionContent, 
      GROUP_CONCAT(DISTINCT Answer ORDER BY Answer SEPARATOR '') AS Answer, 
    q.QuestionMarks 
    FROM Session s 
    INNER JOIN Question q ON s.SessionId = q.SessionId
    JOIN Answer an ON q.QuestionId = an.QuestionId AND an.SessionId = q.SessionId
    WHERE s.SessionName = ?
    GROUP BY an.SessionId, an.QuestionId
    ORDER BY q.QuestionId, an.Answer
    ";

    // prepare query
    $stmt=$mysqli->prepare($query);
    // You only need to call bind_param once
    $stmt->bind_param("s", $assessment);
    // execute query
    $stmt->execute(); 

    // This will hold the search results
    $searchQuestionId = array();
    $searchQuestionContent = array();
    $searchAnswer = array();

    // Fetch the results into an array
    // get result and assign variables (prefix with db)
    $stmt->bind_result($dbQuestionId, $dbQuestionContent, $dbAnswer);
    while ($stmt->fetch()) {
    $searchQuestionId[] = $dbQuestionId;
    $searchQuestionContent[] = $dbQuestionContent;
    $searchAnswer[] = $dbAnswer;
    }   
    ?>      
    </head>
    <body>
    <form id="QandA" action="<?php echo htmlentities($_SERVER['PHP_SELF']); ?>" method="post">
    <?php 
echo "<table border='1' id='markstbl'>
      <tr>
      <th class='questionth'>Question No.</th>
      <th class='questionth'>Question</th>
      <th class='answerth'>Answer</th>
      <th class='answermarksth'>Marks per Answer</th>
      <th class='noofmarksth'>Total Marks</th>
      </tr>\n";
      $previous_question_id = null;
      foreach ($searchQuestionContent as $key=>$question) {
        if ($previous_question_id == $searchQuestionId[$key]) {
      $searchQuestionId[$key] = '';
      $question = '';
  }else{
      $previous_question_id = $searchQuestionId[$key];
  }
        echo '<tr class="questiontd">'.PHP_EOL;
        echo '<td class="optiontypetd">'.htmlspecialchars($searchQuestionId[$key]).'</td>' . PHP_EOL;
        echo '<td>'.htmlspecialchars($question).'</td>' . PHP_EOL;
        echo '<td class="answertd">';
        echo $searchAnswer[$key];
        echo '</td>' ;
        echo '<td class="answermarkstd"><input class="individualMarks" name="answerMarks[]" id="individualtext" type="text" "/></td>' . PHP_EOL;
        echo '<td class="noofmarkstd">'.htmlspecialchars($searchMarks[$key]).'</td>' . PHP_EOL;
}
        echo "</table>" . PHP_EOL;

    ?>
    </form>
    </body>

以下是会话，问题和答案表的内容：

会议桌：

SessionId (auto)  SessionName
1                 AAA
2                 AAB

问题表：

SessionId  QuestionId (auto)  QuestionContent
1          1                  What is 2+2?
1          2                  Name the 3 hobbits?

答案表：

AnswerId (auto) SessionId  QuestionId   Answer
1               1          1           B   
2               1          2           B
3               1          2           C
4               1          2           E

Answer 1

将GROUP_CONCAT(DISTINCT Answer ORDER BY Answer SEPARATOR '') AS Answer更改为Answer并尝试在foreach循环中进行此更改。

$previous_question_id = null;
foreach ($searchQuestionContent as $key=>$question) {
  if ($previous_question_id == $searchQuestionId[$key]) {
    $searchQuestionId[$key] = '';
    $question = '';
  } else {
    $previous_question_id = $searchQuestionId[$key];
  }

想要正确显示html表中的数据

1 个答案: