我正在创建一些我希望从一种颜色淡化到另一种颜色的自定义Swing组件。目前我正在从RGB转换为HSB,然后通过Hue值递增并在绘画前转换回RGB,工作正常。
然而,这会循环所有颜色(即试图从蓝色渐变为绿色循环,通过黄色,橙色,红色等)。是否有一种不错的算法/方法可以直接从一种颜色淡入另一种颜色?
编辑:我已经通过Swing Timer对其进行了更新(我尝试避免使用像瘟疫这样的线程来触摸组件)。今天晚上我会带着你的建议去感谢,谢谢!
答案 0 :(得分:5)
根据此example,下面的Queue<Color>
会从Color.green
到Color.blue
再次循环,并在Color.green
步骤中再次回到N = 32
。请注意,Color.green
在数字上小于HSB模型中的Color.blue
。另请参阅使用HSB的相关example。
public Flash(JComponent component) {
this.component = component;
float gHue = Color.RGBtoHSB(0, 1, 0, null)[0];
float bHue = Color.RGBtoHSB(0, 0, 1, null)[0];
for (int i = 0; i < N; i++) {
clut.add(Color.getHSBColor(gHue + (i * (bHue - gHue) / N), 1, 1));
}
for (int i = 0; i < N; i++) {
clut.add(Color.getHSBColor(bHue - (i * (bHue - gHue) / N), 1, 1));
}
}
答案 1 :(得分:3)
我使用多种方法组合来实现相同的结果。
Baiscally我使用simular API接口作为LinearGradientPaint
,我提供了一系列分数和一组颜色,然后基于float
百分比,我计算得到的混合颜色。
这允许我通过相同的算法产生许多有效的结果。
虽然此示例旨在演示各种颜色的混合,但您可以为两种颜色提供两种颜色和一小部分{0f, 1f}
这使我能够有效地进行彩色动画。
public class ColorFade {
public static void main(String[] args) {
new ColorFade();
}
public ColorFade() {
EventQueue.invokeLater(new Runnable() {
@Override
public void run() {
try {
UIManager.setLookAndFeel(UIManager.getSystemLookAndFeelClassName());
} catch (ClassNotFoundException ex) {
} catch (InstantiationException ex) {
} catch (IllegalAccessException ex) {
} catch (UnsupportedLookAndFeelException ex) {
}
JFrame frame = new JFrame();
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setLayout(new BorderLayout());
// frame.add(new FadePane());
frame.add(new ColorFadePane());
frame.pack();
frame.setLocationRelativeTo(null);
frame.setVisible(true);
}
});
}
public class FadePane extends JPanel {
private float[] fractions = new float[]{0f, 0.25f, 0.5f, 1f};
private Color[] colors = new Color[]{Color.GREEN, Color.BLUE, Color.YELLOW, Color.RED};
private float direction = 0.05f;
private float progress = 0f;
public FadePane() {
Timer timer = new Timer(125, new ActionListener() {
@Override
public void actionPerformed(ActionEvent e) {
if (progress + direction > 1f) {
direction = -0.05f;
} else if (progress + direction < 0f) {
direction = 0.05f;
}
progress += direction;
repaint();
}
});
timer.setCoalesce(true);
timer.setRepeats(true);
timer.start();
}
@Override
public Dimension getPreferredSize() {
return new Dimension(100, 100);
}
@Override
protected void paintComponent(Graphics g) {
super.paintComponent(g);
Graphics2D g2d = (Graphics2D) g.create();
int width = getWidth();
int height = getHeight();
Color startColor = blendColors(fractions, colors, progress);
g2d.setColor(startColor);
g2d.fillRect(0, 0, width, height);
g2d.dispose();
}
}
public class ColorFadePane extends JPanel {
private float[] fractions = new float[]{0f, 0.25f, 0.5f, 1f};
private Color[] colors = new Color[]{Color.GREEN, Color.BLUE, Color.YELLOW, Color.RED};
public ColorFadePane() {
}
@Override
public Dimension getPreferredSize() {
return new Dimension(200, 100);
}
@Override
protected void paintComponent(Graphics g) {
super.paintComponent(g);
Graphics2D g2d = (Graphics2D) g.create();
int width = getWidth();
int height = getHeight();
int bandWidth = width / 100;
for (int index = 0; index < 100; index++) {
float progress = (float)index / (float)100;
Color color = blendColors(fractions, colors, progress);
int x = bandWidth * index;
int y = 0;
g2d.setColor(color);
g2d.fillRect(x, y, bandWidth, height);
}
g2d.dispose();
}
}
public static Color blendColors(float[] fractions, Color[] colors, float progress) {
Color color = null;
if (fractions != null) {
if (colors != null) {
if (fractions.length == colors.length) {
int[] indicies = getFractionIndicies(fractions, progress);
float[] range = new float[]{fractions[indicies[0]], fractions[indicies[1]]};
Color[] colorRange = new Color[]{colors[indicies[0]], colors[indicies[1]]};
float max = range[1] - range[0];
float value = progress - range[0];
float weight = value / max;
color = blend(colorRange[0], colorRange[1], 1f - weight);
} else {
throw new IllegalArgumentException("Fractions and colours must have equal number of elements");
}
} else {
throw new IllegalArgumentException("Colours can't be null");
}
} else {
throw new IllegalArgumentException("Fractions can't be null");
}
return color;
}
public static int[] getFractionIndicies(float[] fractions, float progress) {
int[] range = new int[2];
int startPoint = 0;
while (startPoint < fractions.length && fractions[startPoint] <= progress) {
startPoint++;
}
if (startPoint >= fractions.length) {
startPoint = fractions.length - 1;
}
range[0] = startPoint - 1;
range[1] = startPoint;
return range;
}
public static Color blend(Color color1, Color color2, double ratio) {
float r = (float) ratio;
float ir = (float) 1.0 - r;
float rgb1[] = new float[3];
float rgb2[] = new float[3];
color1.getColorComponents(rgb1);
color2.getColorComponents(rgb2);
float red = rgb1[0] * r + rgb2[0] * ir;
float green = rgb1[1] * r + rgb2[1] * ir;
float blue = rgb1[2] * r + rgb2[2] * ir;
if (red < 0) {
red = 0;
} else if (red > 255) {
red = 255;
}
if (green < 0) {
green = 0;
} else if (green > 255) {
green = 255;
}
if (blue < 0) {
blue = 0;
} else if (blue > 255) {
blue = 255;
}
Color color = null;
try {
color = new Color(red, green, blue);
} catch (IllegalArgumentException exp) {
NumberFormat nf = NumberFormat.getNumberInstance();
System.out.println(nf.format(red) + "; " + nf.format(green) + "; " + nf.format(blue));
exp.printStackTrace();
}
return color;
}
}
答案 2 :(得分:1)
提示
x
Tadaaaa ..: - )
更新:如果您愿意,可以玩x
的价值。
使用Math.Random()
函数在执行期间为x
生成伪随机值
HovercraftFullOfEels&amp; mKorbel,感谢您的投入
答案 3 :(得分:1)
最简单的方法是在每个RGB值之间进行插值。 这对所有语言都是一样的 - python代码看起来像:
steps = 10
rgb1 = [ 'AA', '08', 'C3' ]
rgb2 = [ '03', '88', '1C' ]
h1 = map( lambda s: int( '0x'+s, 0 ), rgb1 )
h2 = map( lambda s: int( '0x'+s, 0 ), rgb2 )
inc = [0, 0, 0]
for i in range(0,3):
inc[i] = ( h2[i] - h1[i] ) / ( steps - 1 )
for i in range(0,steps-1):
print '<span style="background: #%02x%02x%02x"> %i </span>' % (
h1[0] + i * inc[0],
h1[1] + i * inc[1],
h1[2] + i * inc[2],
i+1 )
print '<span style="background: #%02x%02x%02x"> %i </span>' % (
h2[0], h2[1], h2[2], steps )
答案 4 :(得分:0)
您可以线性插值从开始rgb颜色到最后想要的颜色的过渡。
这意味着,例如您以rgb(255,255,0)
作为起始颜色并以rgb(50,50,50)
作为目标,并希望在导致以下颜色的每个步骤中按(-41 = (255-50)/5, -41, 10)
调整的5个步骤中达到最终颜色:
rgb(255,255, 0)
rgb(214,214, 10)
rgb(173,173, 20)
rgb(132,132, 30)
rgb( 91, 91, 40)
rgb( 50, 50, 50)
这称为线性渐变,非常容易实现,但当然还有各种其他技术可以在颜色之间进行很好的过渡。