我将每个月从数据库中计算每个观众。我尝试了很多方法,但我没有运气。这是代码示例
SELECT MONTH_v, YEAR_V,
SUM(IF(day_v=1, views, 0)) AS '1',
SUM(IF(day_v=2, views, 0)) AS '2',
SUM(IF(day_v=3, views, 0)) AS '3',
SUM(IF(day_v=4, views, 0)) AS '4',
SUM(IF(day_v=5, views, 0)) AS '5',
SUM(IF(day_v=6, views, 0)) AS '6',
SUM(IF(day_v=7, views, 0)) AS '7',
SUM(IF(day_v=8, views, 0)) AS '8',
SUM(IF(day_v=9, views, 0)) AS '9',
SUM(IF(day_v=10, views, 0)) AS '10',
SUM(IF(day_v=11, views, 0)) AS '11',
SUM(IF(day_v=12, views, 0)) AS '12',
SUM(IF(day_v=13, views, 0)) AS '13',
SUM(IF(day_v=14, views, 0)) AS '14',
SUM(IF(day_v=15, views, 0)) AS '15',
SUM(IF(day_v=16, views, 0)) AS '16',
SUM(IF(day_v=17, views, 0)) AS '17',
SUM(IF(day_v=18, views, 0)) AS '18',
SUM(IF(day_v=19, views, 0)) AS '19',
SUM(IF(day_v=20, views, 0)) AS '20',
SUM(IF(day_v=21, views, 0)) AS '21',
SUM(IF(day_v=22, views, 0)) AS '22',
SUM(IF(day_v=23, views, 0)) AS '23',
SUM(IF(day_v=24, views, 0)) AS '24',
SUM(IF(day_v=25, views, 0)) AS '25',
SUM(IF(day_v=26, views, 0)) AS '26',
SUM(IF(day_v=27, views, 0)) AS '27',
SUM(IF(day_v=28, views, 0)) AS '28',
SUM(IF(day_v=29, views, 0)) AS '29',
SUM(IF(day_v=30, views, 0)) AS '30',
SUM(IF(day_v=31, views, 0)) AS '31'
FROM
(
SELECT DAY(vwr_date) AS day_v,
MONTH(vwr_date) AS MONTH_v,
Year(vwr_date) AS YEAR_V,
date(vwr_date) AS date_v,
count(vwr_id) AS views
FROM car_viewer
WHERE Year(vwr_date)='2012' AND vwr_tid='18'
GROUP BY date_v
) as viewz
GROUP BY MONTH_v, YEAR_V
ORDER BY MONTH_v, YEAR_V DESC;
实时视图位于:http://www.sqlfiddle.com/#!2/75aa8/1
问题是我想在每行的右侧添加两列:
请不要犹豫,伸出援助之手。 :)
参考:MySQL count(*) everyday in a month returns [BLOB-2B] instead of number
信用:罗斯史密斯二世
答案 0 :(得分:2)
只需在外部查询中添加SUM(views)
:
SELECT MONTH_v, YEAR_V,
...
SUM(IF(day_v=30, views, 0)) AS '30',
SUM(IF(day_v=31, views, 0)) AS '31',
SUM(views)
FROM
(
SELECT DAY(vwr_date) AS day_v,
....