Question

我想准备一个带2个参数的过程（Int，string）如果表格中存在某些行，我会得到@dane = 1;最后我想选择@dane，但我的程序并不好。我不能使用return @dane。

    USE [SS]
    GO

    SET ANSI_NULLS ON
    GO
    SET QUOTED_IDENTIFIER ON
    GO

    CREATE PROCEDURE [permission].[CheckSkill] 
(
    @SkillId INT, -- Identyfikator użytkownika 
    @Description NVARCHAR(100) = NULL
)
AS
BEGIN
    SET NOCOUNT ON;
    DECLARE @dana as int
    SET @dana = 0

    -- this is redundant:
    --SET @Description = RTRIM(LTRIM(ISNULL(@Description,'')))

    IF EXISTS (SELECT * FROM permission.UserXSkill Where permission.UserXSkill.SkillId = @SkillId)
    BEGIN
      SET @dana = 1;
    END

    SELECT @dana AS ID;
END
GO

主题[已关闭]感谢您的帮助。

Answer 1

在为变量指定值时，您需要使用SET或SELECT。

EXISTS似乎符合IF块

中的要求

@Description参数未使用且是多余的

USE [SS]
GO

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO

CREATE PROCEDURE [permission].[CheckSkill] 
(
    @SkillId INT, -- Identyfikator użytkownika 
    @Description NVARCHAR(100) = NULL,

)
AS
BEGIN
    SET NOCOUNT ON;
    DECLARE @dana as int
    SET @dana = 0

    -- this is redundant:
    --SET @Description = RTRIM(LTRIM(ISNULL(@Description,'')))

    IF EXISTS (SELECT * FROM permission.UserXSkill Where permission.UserXSkill = @SkillId)
    BEGIN
      SET @dana = 1;
    END

    SELECT @dana AS ID;
END
GO

MSSQL - 返回选择

1 个答案: