Question

我正在编写一个代码，使用hashCompute方法对给定目录中的相等文件进行分组。我完成了大部分工作，但我似乎无法对文件进行分组。我希望将具有相同哈希值的文件组合在一起。

以下是我的代码示例：

public static void myhashedfiles()
{
    string directory;
    Console.WriteLine("please enter a folder name:");
    directory = (Console.ReadLine());

    if (directory.Length < 1)
    {
        Console.WriteLine("enter a directory or folder name!");
        return;
    }

    DirectoryInfo dir = new DirectoryInfo(directory);
    try
    {
        FileInfo[] files = dir.GetFiles("*.*", System.IO.SearchOption.AllDirectories);

        HashAlgorithm hash = HashAlgorithm.Create();

        byte[] hashValue;

        foreach (FileInfo fInfo in files)
        {
            FileStream fileStream = fInfo.Open(FileMode.Open);
            fileStream.Position = 0;

            hashValue = hash.ComputeHash(fileStream);

            PrintByteArray(hashValue);
            Console.WriteLine(fInfo.Name);

            fileStream.Close();
        }
    }
    catch (DirectoryNotFoundException)
    {
        Console.WriteLine("Error: The directory specified could not be found.");
    }
    catch (IOException)
    {
        Console.WriteLine("Error: A file in the directory could not be accessed.");
    }
}

Answer 1

你可以这样做：

var groups = files
    .Select(file => new {
        fInfo = file,
        Hash = hash.ComputeHash(file.Open(FileMode.Open)) }
    ).GroupBy(item => item.Hash);

foreach (var grouping in groups)
{
    Console.WriteLine("Files with hash value: {0}", grouping.Key);
    foreach(var item in grouping)
        Console.WriteLine(item.fInfo);
}

将目录中的相等文件分组

1 个答案: