iOS Facebook SDK:必须使用活动访问令牌来查询有关当前用户的信息

时间:2012-10-29 18:08:54

标签: ios facebook facebook-ios-sdk

我已经关注了许多示例,并查看了有关此访问令牌错误的许多问题,但我似乎无法找到我获取它或如何修复它的原因。

我像在3.1 sdk示例中那样启动Facebook:

 NSArray* permissions = [[NSArray alloc] initWithObjects:@"publish_stream", @"publish_actions", nil];
 self.fb = [[FBSession alloc] initWithPermissions:permissions];
 [self.fb openWithCompletionHandler:^(FBSession *session,
                                         FBSessionState status,
                                         NSError *error)
     {
         [self sessionStateChanged:session :status :error];
     }];

此工作正常,并要求用户在Safari中接受应用程序权限,然后返回到应用程序。当用户返回到应用程序时,我的FBSessionState是FBSessionStateOpen。​​

当我尝试这个时:

[FBRequestConnection startForMeWithCompletionHandler:^(FBRequestConnection *connection, id result, NSError *error)
                 {

                     [self showAlert:@"logged in?" result:result error:error];
                 }];

或者这个:

NSMutableDictionary* fbPost = [[NSMutableDictionary alloc] initWithObjectsAndKeys:@"post from iOS", @"message", nil];
[FBRequestConnection startWithGraphPath:@"me/feed" parameters:fbPost HTTPMethod:@"POST" completionHandler:^(FBRequestConnection *connection, id result, NSError *error)
                                        {

                                            [self showAlert:@"message posted?" result:result error:error];
                                        }];

但我明白了:

FBSDKLog: FBURLConnection <#1126>:

  Duration: 936 msec

Response Size: 0 kB

  MIME type: text/javascript

  Response:

{"error":{"message":"An active access token must be used to query information about the current user.","type":"OAuthException","code":2500}}

我从我的FBSession获取了访问令牌并将其放入Facebook的访问令牌调试器中,它显示我有一个很好的令牌:

App ID: <hidden>
Metadata: {"sso":"iphone-safari"}
User ID: <hidden>
Issued:  1351525817 (about an hour ago)
Expires: 1356709817 (in about 2 months)
Valid:  True
Origin: Mobile Web Faceweb
Scopes: create_note photo_upload publish_actions publish_stream share_item status_update video_upload

我必须错过设置中的一些小细节或其他东西。

提前谢谢大家!

5 个答案:

答案 0 :(得分:29)

根据文档https://developers.facebook.com/docs/reference/ios/3.1/class/FBRequestConnection

“请求使用[FBSession activeSession]表示的活动会话。”

这适用于处理请求的静态方法。所以你要做的是确保你设置活动会话。执行以下操作:

[FBSession setActiveSession:self.fb];

在您调用第一个FBRequestConnection start *方法之前。

答案 1 :(得分:11)

好一段时间后,注意到FBSession.activeSession不是nil,我在发送请求之前缺少的是:

    if (!FBSession.activeSession.isOpen) {
        [FBSession openActiveSessionWithAllowLoginUI: YES];
    }

答案 2 :(得分:1)

当我尝试使用在登录前创建的FBSDKGraphRequest对象时,我在SDK的第4版中遇到此错误。当我在使用之前将其更改为创建FBSDKGraphRequest时(即之后)已登录)它工作正常。看来这个类的初始化程序设置了一些在请求启动时没有刷新的标记。

我在登录后尝试更新请求的tokenString属性,但由于某种原因,这是readonly属性。

答案 3 :(得分:0)

/ *      谷歌和脸书网已弃用     func application(_ application:UIApplication,open url:URL,sourceApplication:String?,annotation:AnyObject) - &gt;布尔{         让googleDidHandle = GIDSignIn.sharedInstance()。handle(url,                                                                    sourceApplication:sourceApplication,                                                                    注释:注释)

    let facebookDidHandle = FBSDKApplicationDelegate.sharedInstance().application(
        application,

打开:网址,             sourceApplication:sourceApplication,             注释:注释)         打印(facebookDidHandle)         返回googleDidHandle || facebookDidHandle     }    * /

所以我用过,  func应用程序(_ application:UIApplication,                      open url:URL,options:[String:AnyObject]) - &gt;布尔     {

    return FBSDKApplicationDelegate.sharedInstance().application(application, didFinishLaunchingWithOptions: options) || GIDSignIn.sharedInstance().handle(url as URL!, sourceApplication: options[UIApplicationOpenURLOptionsSourceApplicationKey] as! String, annotation: options[UIApplicationOpenURLOptionsAnnotationKey])
}

xcode 8 beta 3,ios 10

答案 4 :(得分:0)

你也可以尝试这个,对我有用

func application(_ application: UIApplication,
                      open url: URL, 
                       options: [String: AnyObject]) -> Bool
{
    let delegate = FBSDKApplicationDelegate.sharedInstance()

    return delegate.application(application, open: url, 
                                sourceApplication: options["UIApplicationOpenURLOptionsSourceApplicationKey"] as! String, 
                                       annotation: options["UIApplicationOpenURLOptionsAnnotationKey"])
}