在R中创建累积步骤图

Question

说我有这个示例数据框

set.seed(12345)
n1 <- 3
n2 <- 10
n3 <- 60

times <- seq(0, 100, 0.5)

individual <- c(rep(1, n1), 
                rep(2, n2), 
                rep(3, n3))

events <- c(sort(sample(times, n1)),
            sort(sample(times, n2)),
            sort(sample(times, n3)))

df <- data.frame(individual = individual, events = events)

哪个给出了

> head(df, 10)
   individual events
1           1   72.0
2           1   75.5
3           1   87.5
4           2    3.0
5           2   14.5
6           2   16.5
7           2   32.0
8           2   45.5
9           2   50.0
10          2   70.5

我想绘制事件的累积步骤图，以便每个人获得一行，每次“遇到”事件时，每行增加1。

因此，例如，个体1将是0到72.0，然后上升到1，直到75.5，当它变为2时，最多3到87.5到图的末尾。

最简单的方法是什么？

Answer 1

df$step <- 1

library(plyr)
df <- ddply(df,.(individual),transform,step=cumsum(step))

plot(step~events,data=df[df$individual==1,],type="s",xlim=c(0,max(df$events)),ylim=c(0,max(df$step)),xlab="time",ylab="step")
lines(step~events,data=df[df$individual==2,],type="s",col=2)
lines(step~events,data=df[df$individual==3,],type="s",col=3)

Answer 2

使用ggplot2：

library(ggplot2)

# Add step height information with sequence and rle
df$step <- sequence(rle(df$individual)$lengths)

# plot
df$individual <- factor(df$individual)
ggplot(df, aes(x=events, group=individual, colour=individual, y=step)) + 
  geom_step()

Answer 3

stats包中还有stepfun函数。使用它，您可以对该对象类使用plot方法：

sdf <- split(df, individual)

plot(1, 1, type = "n", xlim = c(0, max(events)), ylim = c(0, max(table(individual))),
  ylab = "step", xlab = "time")

sfun <- lapply(sdf, function(x){
    sf <- stepfun(sort(x$events), seq_len(nrow(x) + 1) - 1)
    plot(sf, add = TRUE, col = unique(x$individual), do.points = FALSE)
})