下面我有一个T-SQL查询,可以带回购买的商品数量,减去折扣和总数 - 按购买月份/年份分组。如何更新查询以返回总计行 我可以将总额中的金额相加? 能够将所有行添加到我的网站会很好 主要项目是我需要能够得到一个总计。感谢。
Select DATENAME(month, [OrderDate]) + ' ' + CAST(YEAR(OrderDate) AS CHAR(4))
AS [Month],
SUM(Amount) AS [Amount],
SUM(Discount1) AS [Discount 1],
SUM(Discount2) AS [Discount 2],
SUM(Amount - Discount1 - Discount2) AS [Total]
From
Orders
JOIN Customer on orders.cust_ky=customer.cust_ky
GROUP BY DATENAME(month, [OrderDate]) + ' ' + CAST(YEAR(OrderDate) AS CHAR(4))
ORDER BY MAX(OrderDate)
答案 0 :(得分:6)
根据您的sql-server版本,您可能能够实现汇总功能(SQL-Server 2005 +):
Select DATENAME(month, [OrderDate]) + ' ' + CAST(YEAR(OrderDate) AS CHAR(4)) AS [Month],
SUM(Amount) AS [Amount],
SUM(Discount1) AS [Discount 1],
SUM(Discount2) AS [Discount 2],
SUM(Amount - Discount1 - Discount2) AS [Total]
From Orders
JOIN Customer
on orders.cust_ky=customer.cust_ky
GROUP BY ROLLUP(DATENAME(month, [OrderDate]) + ' ' + CAST(YEAR(OrderDate) AS CHAR(4)))
ORDER BY MAX(OrderDate)
或者您可以使用与此类似的UNION ALL
,其中第二个查询获得的总数不包含GROUP BY
:
Select DATENAME(month, [OrderDate]) + ' ' + CAST(YEAR(OrderDate) AS CHAR(4)) AS [Month],
SUM(Amount) AS [Amount],
SUM(Discount1) AS [Discount 1],
SUM(Discount2) AS [Discount 2],
SUM(Amount - Discount1 - Discount2) AS [Total]
From Orders
JOIN Customer
on orders.cust_ky=customer.cust_ky
GROUP BY DATENAME(month, [OrderDate]) + ' ' + CAST(YEAR(OrderDate) AS CHAR(4))
union all
Select 'Total',
SUM(Amount) AS [Amount],
SUM(Discount1) AS [Discount 1],
SUM(Discount2) AS [Discount 2],
SUM(Amount - Discount1 - Discount2) AS [Total]
From Orders
JOIN Customer
on orders.cust_ky=customer.cust_ky