我在条件中得到了sql问题:
$select->where('(users.user_fname LIKE (?) )','%'.$first.'%');
如何输入或条件使它看起来像:
$select->where('(users.user_fname LIKE (?) )','%'.$first.'%');
OR
$select->where('(users.user_fname LIKE (?) )','%'.$last.'%');
答案 0 :(得分:1)
http://framework.zend.com/manual/1.12/en/zend.db.select.html
$select
->where('(users.user_fname LIKE "%?%")', $first)
->orWhere('(users.user_fname LIKE "%?%")', $last)
;