我是android的新手,我想创建一个从mysql服务器读取数据的应用程序。 I've taken from web an example about this,但我无法使其发挥作用
我正在使用eclipse和其他部分,php和mysql。 首先,这是我的php脚本运行正常(city.php):
<?php
//connecting to database
$sql=mysql_query("select * from city");
$output = array();
while(list($id,$name)=mysql_fetch_array($sql)){
$output[$id]=$name;
}
print(json_encode($output));
mysql_free_result($sql);
?>
这是回归:
{"1":"Brasov","2":"Bucuresti"}
在我的eclipse的android项目中,我有MainActivity.java:
package com.example.mycity;
import android.os.Bundle;
import android.app.Activity;
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.net.ParseException;
import android.util.Log;
import android.widget.Toast;
public class MainActivity extends Activity {
JSONArray jArray;
String result = null;
InputStream is = null;
StringBuilder sb=null;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
//http post
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://www.steagu.ro/android/city.php");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
if (response.getStatusLine().getStatusCode() != 200) {
Log.d("MyApp", "Server encountered an error.");
}
HttpEntity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e){
//e.printStackTrace();
Log.e("log_tag", "Error in http connection: "+e.toString());
}
}
}
但是当我运行它时,我在logcat上收到一个错误:它没有连接到文件:http连接错误:android.os.NetworkOnMainThreadException
10-24 13:04:34.429: I/dalvikvm(982): threadid=3: reacting to signal 3
10-24 13:04:34.649: I/dalvikvm(982): Wrote stack traces to '/data/anr/traces.txt'
10-24 13:04:34.859: E/log_tag(982): Error in http connection: android.os.NetworkOnMainThreadException
10-24 13:04:34.919: I/dalvikvm(982): threadid=3: reacting to signal 3
10-24 13:04:34.949: I/dalvikvm(982): Wrote stack traces to '/data/anr/traces.txt'
10-24 13:04:35.151: D/gralloc_goldfish(982): Emulator without GPU emulation detected.
10-24 13:04:35.479: I/dalvikvm(982): threadid=3: reacting to signal 3
10-24 13:04:35.499: I/dalvikvm(982): Wrote stack traces to '/data/anr/traces.txt'
我在AndroidManifest.xml中拥有互联网权限:
<manifest xmlns:android="http://schemas.android.com/apk/res/android"
package="com.example.mycity"
android:versionCode="1"
android:versionName="1.0" >
<uses-sdk
android:minSdkVersion="8"
android:targetSdkVersion="15" />
<uses-permission android:name="android.permission.INTERNET"></uses-permission>
<uses-permission android:name="android.permission.ACCESS_WIFI_STATE"></uses-permission>
<uses-permission android:name="android.permission.WRITE_EXTERNAL_STORAGE"></uses-permission>
<application
android:icon="@drawable/ic_launcher"
android:label="@string/app_name"
android:theme="@style/AppTheme" >
<activity
android:name=".MainActivity"
android:label="@string/title_activity_main" >
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
</application>
</manifest>
我不知道问题出在哪里。任何人都可以帮我吗?谢谢!
答案 0 :(得分:0)
问题在于:
10-24 13:04:34.859: E/log_tag(982): Error in http connection:
android.os.NetworkOnMainThreadException
您需要在其他线程上进行网络访问。
答案 1 :(得分:0)
您可以使用AsyncTask类来执行网络操作,因为strictmode不允许在主UI示例上完成,如下所示
public class MainActivity extends Activity {
JSONArray jArray;
String result = null;
InputStream is = null;
StringBuilder sb=null;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
new httpRequest().execute();
}
private class httprRequest extends AsyncTask<String, Integer, String>{
@override
public String doInBackground(String.... params){
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
//http post
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://www.steagu.ro/android/city.php");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
if (response.getStatusLine().getStatusCode() != 200) {
Log.d("MyApp", "Server encountered an error.");
}
HttpEntity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e){
//e.printStackTrace();
Log.e("log_tag", "Error in http connection: "+e.toString());
}
}
}
}
}
答案 2 :(得分:-1)
谢谢kabuto178,我做了改动而且正在连接。我也编写了代码来从mysql中检索数据,所以谁需要这个,可以使用我的例子
以下是代码:
package com.example.mycity;
import android.os.AsyncTask;
import android.os.Bundle;
import android.app.Activity;
import java.io.BufferedReader;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.util.ArrayList;
import org.apache.http.HttpEntity;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.client.HttpClient;
import org.apache.http.client.entity.UrlEncodedFormEntity;
import org.apache.http.client.methods.HttpPost;
import org.apache.http.impl.client.DefaultHttpClient;
import org.json.JSONArray;
import org.json.JSONException;
import org.json.JSONObject;
import android.net.ParseException;
import android.util.Log;
import android.widget.TextView;
import android.widget.Toast;
public class MainActivity extends Activity {
String result = "";
InputStream is = null;
StringBuilder sb=null;
//String ct_name = null;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
new httprRequest().execute();
int ct_id=0;
String ct_name="";
//Toast.makeText(getBaseContext(), "This is "+result, 3000).show();
try {
Thread.sleep(1000L);
} catch (Exception te) {}
try{
//ct_name = result;
JSONArray jArray = new JSONArray(result);
for(int i=0;i<jArray.length();i++){
JSONObject json_data= jArray.getJSONObject(i);
ct_id=json_data.getInt("CITY_ID");
ct_name += json_data.getString("CITY_NAME")+":";
}
}
catch(JSONException e1){
e1.printStackTrace();
} catch (ParseException e1) {
e1.printStackTrace();
}
TextView tv1 = (TextView) findViewById(R.id.textView1);
tv1.setText(ct_name);
}
private class httprRequest extends AsyncTask<String, Integer, String>{
@Override
public String doInBackground(String... params){
ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
//http post
try{
HttpClient httpclient = new DefaultHttpClient();
HttpPost httppost = new HttpPost("http://www.steagu.ro/android/city.php");
httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
HttpResponse response = httpclient.execute(httppost);
if (response.getStatusLine().getStatusCode() != 200) {
Log.d("MyApp", "Server encountered an error.");
}
HttpEntity entity = response.getEntity();
is = entity.getContent();
}catch(Exception e){
//e.printStackTrace();
Log.e("log_tag", "Error in http connection: "+e.toString());
}
//convert response to string
try{
BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);
sb = new StringBuilder();
sb.append(reader.readLine() + "\n");
String line="0";
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
result=sb.toString();
}catch(Exception e){
//Toast.makeText(getBaseContext(), "Am eroare aici", 3000).show();
Log.e("log_tag", "Error converting result "+e.toString());
}
/*
Toast.makeText(getBaseContext(), "Here i am", 3000).show();
*/
return result;
}
}
}
我必须更改一点代码,因为我放了一个thread.sleep。而不是它,我必须检查我是否有一个值到结果(在一个while循环)。我认为这种情况正在发生,因为在我试图解析价值的那一刻,我没有结果的价值。
php代码是:
<?php
//connecting to database
$sql=mysql_query("select * from city where CITY_NAME like '%'");
$output = array();
while($row=mysql_fetch_assoc($sql)){
$output[]=$row;
}
echo json_encode($output);
mysql_free_result($sql);
?>
表'city'有两列,CITY_ID和CITY_NAME。