我有一张包含日期列的5000条记录的表格。
如何找到这些日期的平均值。我试过了AVG(datefield)
,但它说Operand data type datetime is invalid for avg operator
答案 0 :(得分:23)
如果您只想平均日期:
SELECT CAST(AVG(CAST(datefield AS INT)) AS DATETIME) FROM dates;
如果你想考虑时间:
SELECT CAST(AVG(CAST(datefield AS FLOAT)) AS DATETIME) FROM dates;
请参阅fiddle进行测试。
答案 1 :(得分:6)
CONVERT(DATETIME, AVG(CONVERT(FLOAT, datefield))) as [AverageDate]
答案 2 :(得分:0)
对于那些遇到转换错误(无法将日期转换为int或float的人)...
这是使用datediff
和dateadd
SELECT
DATEADD(DAY, AVG(DATEDIFF(DAY, '1900-01-01', datefield)), '1900-01-01') AS [AverageDate]
FROM dates;
请注意,1900年1月1日是任意日期,两个地方都必须相同。
答案 3 :(得分:0)
我做了这个,希望以后能帮到其他人! SQL 很糟糕,因为它没有让这变得更容易。
Declare @Day as int;
Declare @Month as int;
Declare @Year as int;
Declare @Date as varchar(50);
SET @Day = (SELECT AVG(DAY(Column_name)) FROM Table_Name)
SET @Month = (SELECT AVG(MONTH(Column_name)) FROM Table_Name)
SET @Year = (SELECT AVG(YEAR(Column_name)) FROM Table_Name)
SET @Date = CAST(@Day as varchar) +'-' + CAST(@Month as varchar) + '-' + CAST(@Year as varchar);
SELECT CONVERT(datetime2,@Date,103)