Question

这是我在http://www.w3resource.com/twitter-bootstrap/typehead.php

找到的代码

<!DOCTYPE html>  
<html>  
<head>  
    <meta charset="utf-8" />  
    <title>Bootstrap typehead example by w3resource</title>  
    <link href="http://www.w3resource.com/twitter-bootstrap/twitter-bootstrap-v2/docs/assets/css/bootstrap.css" rel="stylesheet" type="text/css" />  
</head>  
<body>  
<div class="well">  
<input type="text" class="span3" style="margin: 0 auto;" data-provide="typeahead" data-items="4" data-source='["Ahmedabad","Akola","Asansol","Aurangabad","Bangaluru","Baroda","Belgaon","Berhumpur","Calicut","Chennai","Chapra","Cherapunji"]'>  
</div>  
<script src="http://www.w3resource.com/twitter-bootstrap/twitter-bootstrap-v2/docs/assets/js/jquery.js"></script>  
<script src="http://www.w3resource.com/twitter-bootstrap/twitter-bootstrap/twitter-bootstrap-v2/docs/assets/js/bootstrap-typeahead.js"></script>  
</body>  
</html>

它正在运行，但我想在其中添加一个小功能。我想在列表中创建一个始终显示在列表底部的链接。因此，如果您键入内容，则会过滤列表，但底部的链接将始终显示。

Answer 1

这个想法只是扩展typehead原型以重新定义它的渲染方法：

var uber = {render: $.fn.typeahead.Constructor.prototype.render};
$.extend($.fn.typeahead.Constructor.prototype, {
    render: function(items) {
        uber.render.call(this, items);
        this.$menu.append('<li class="nostyle"><a href="#" onclick="alert(123)">some link</a></li>')
        return this;
    }
});

请参阅此演示http://jsfiddle.net/dfsq/8qZd8/2/

始终显示来自bootstrap的typeahead列表中的链接

1 个答案: