Question

CREATE TABLE IF NOT EXISTS `site_location` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `level` int(11) NOT NULL,
  `lft` int(11) NOT NULL,
  `rgt` int(11) NOT NULL,
  `name` varchar(50) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=13 ;

///DATA
    INSERT INTO `site_location` (`id`, `level`, `lft`, `rgt`, `name`) VALUES
    (1, 0, 1, 24, 'United Kingdom'),
    (2, 1, 2, 19, 'London'),
    (3, 2, 13, 14, 'Central London'),
    (4, 2, 11, 12, 'East London'),
    (5, 2, 9, 10, 'North London'),
    (6, 2, 7, 8, 'North West London'),
    (7, 2, 5, 6, 'South East London'),
    (8, 2, 3, 4, 'West London'),
    (9, 2, 15, 18, 'South West'),
    (10, 3, 16, 17, 'Battersea'),
    (11, 1, 20, 23, 'Brighton'),
    (12, 2, 21, 22, 'Guildford');

CREATE TABLE IF NOT EXISTS `ads` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `category_id` int(11) NOT NULL,
  `location` int(11) NOT NULL,
  `title` varchar(255) CHARACTER SET utf8 NOT NULL,
  PRIMARY KEY (`id`,`category_id`)
) ENGINE=InnoDB  DEFAULT CHARSET=latin1 AUTO_INCREMENT=5 ;

INSERT INTO `ads` (`id`, `category_id`, `location`, `title`) VALUES
(1, 7, 10, 'Test1'),
(2, 9, 3, 'Test2'),
(3, 12, 10, 'Test3'),
(4, 13, 4, 'Test4');

当ID为ID = 1时返回

[ United Kingdom(4) ]
    London(4)     
    Brighton(0)

当ID为ID = 2时

    United Kingdom(4)
      [ London(4) ]
        South West(2)
        Central London(1)
        East London(1)
      Brighton(0)

所以当选择“伦敦”时，我需要所有兄弟姐妹及其所有孩子

同样被选为“西南”时我需要所有兄弟姐妹的所有孩子，其父母的所有父母兄弟

    United Kingdom(4)
      London(4)
        [ South West(2) ]
          Battersea(2)
        Central London(1)
        East London(1)
      Brighton(0)

以及在该位置有多少广告，例如在英国必须有4个，因为表中的所有广告都是4，西南必须有2个，因为在巴特西有2个

当id为11时

United Kingdom(4)
  London(4)
  [ Brighton(0) ]
      Guildford(0)

我有一个问题： South West lft：15，rgt：18，level：2

 SELECT 
    node.id, 
    node.alias, 
    node.level, 
    node.name, 
    COUNT(ads.id) as ads,
    IF(node.lft = node.rgt-1, "0", "1") AS `has_children`
 FROM 
    site_location AS parent LEFT JOIN
    ads as ads ON (parent.id = ads.location),
    site_location AS node
 WHERE
    parent.lft BETWEEN node.lft AND node.rgt
 AND 
    parent.lft BETWEEN 15 AND 18
 AND 
    node.level > 0
 AND
   node.level < 2 + 3
 GROUP BY node.id
 ORDER BY node.lft

这将返回

 London(4)
  South West(2)
   Battersea(2)

我需要这样做

 London(4)
  South West(2)
   Battersea(2)
 Brighton(0)

是否可以使用单个查询执行此操作：？如果有人可以提供帮助，那就太好了。提前谢谢！

嵌套类别仅计算带有产品的一个分支

0 个答案: