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Question

我有两张桌子。

Table1-＆GT;付款

AdmissionNum(PK)  |  StudName |   Fees |

       1               sagar      5000 
       2               nilesh     6000
       3               amar       4000

Table2-＆GT; paymentDetails

AdmissionNum(FK) | RemainingFees |   Date       |  Payment
        1             4000          1/1/2012          1000
        2             5000          2/5/2012          1000
        1             3500          2/10/2012         1500
        1             2500          2/15/2012         1000
        2             2500          2/20/2012         2500
        3             0             3/25/2012         4000

我尝试过不同的查询，但无法在付款表和paymentDetails表之间建立联系。我正在制作C＃windows应用程序。当特定学生支付费用时，他的记录存储在paymentDetails表中。我想只提取未付费用的详细信息，即剩余费用大于0的学生，但是在paymentDetais表中的最后一个细节，即

我期望的resut表是 -

AdmissionNum  |  StudName |   Fees | RemainingFees

       1           sagar      5000    2500
       2           nilesh     6000    2500

Answer 1

试试这个：

with cte as (select P.AdmissionNum , P.StudName,   P.Fees , D.RemainingFees,row_number() 
over ( partition by  P.AdmissionNum order by [DATE] desc) as rn
from Payment P
join PaymentDetails D
on P.AdmissionNum=D.AdmissionNum
where RemainingFees>0)
select AdmissionNum ,StudName,  Fees , RemainingFees
from cte
where rn=1

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Answer 2

我会这样做。

SELECT 
       P.AdmissionNum,
       P.StudName,
       P.Fees
       P.Fees - PD.Payment 'RemainingFees'
FROM
    Payment P
    JOIN (SELECT 
                AdmissionNum, 
                SUM(Payment) 'Payment' 
          FROM 
                PaymentDetails 
          GROUP BY AdmissionNum
    ) AS PD
    ON P.AdmissionNum = PD.AdmissionNum
WHERE 
    P.Fees - PD.Payment > 0

Answer 3

尝试以下：

   SELECT a.AdmissionNum, a.StudName , a.Fees, b.remFees as RemainingFees
   FROM Payment a, 
        (SELECT AdmissionNum, min(RemainingFees) as remFees 
           FROM PaymentDetails b GROUP BY AdmissionNum) b
   WHERE a.AdmissionNum = b.AdmissionNum 
        and b.remFees >0;

Answer 4

尝试下面的查询：

Select a.AdmissionNum, a.StudName, a.Fees, b.RemainingFees 
from Payment a 
inner join paymentDetails b on a.AdmissionNum = b.AdmissionNum
inner join (
   select AdmissionNum, max(date) as date 
   from paymentDetails 
   group by AdmissionNum
) c on a.AdmissionNum = c.AdmissionNum
where b.RemainingFees > 0 and b.Date = c.Date

加入不符合描述的条件

4 个答案:

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