Question

如何在Python中获取当月的星期日数？

有人对此有任何想法吗？

Answer 1

这会根据您的需要为您提供当月的星期日数：

import calendar
from datetime import datetime

In [367]: len([1 for i in calendar.monthcalendar(datetime.now().year,
                                  datetime.now().month) if i[6] != 0])
Out[367]: 4

Answer 2

我的看法:(节省了担心在正确的月份等...）

from calendar import weekday, monthrange, SUNDAY

y, m = 2012, 10

days = [weekday(y, m, d+1) for d in range(*monthrange(y, m))]
print days.count(SUNDAY)

或者，正如@mgilson指出的那样，你可以取消list-comp，并将其全部包装为生成器：

sum(1 for d in range(*monthrange(y,m)) if weekday(y,m,d+1)==SUNDAY)

我想，你可以投入：

from collections import Counter
days = Counter(weekday(y, m, d + 1) for d in range(*monthrange(y, m)))
print days[SUNDAY]

Answer 3

我会这样做：

import datetime

today = datetime.date.today()
day = datetime.date(today.year, today.month, 1)
single_day = datetime.timedelta(days=1)

sundays = 0
while day.month == today.month:
    if day.weekday() == 6:
        sundays += 1
    day += single_day

print 'Sundays:', sundays

Answer 4

我碰巧需要一个解决方案，但是这里的解决方案并不令人满意，所以我想出了自己的解决方案：

import calendar

year = 2016
month = 3
day_to_count = calendar.SUNDAY

matrix = calendar.monthcalendar(year,month)

num_days = sum(1 for x in matrix if x[day_to_count] != 0)

Answer 5

使用calendar和datetime的另一个例子：

import datetime
import calendar
today = datetime.date.today()
m = today.month
y = today.year
sum(1 for week in calendar.monthcalendar(y,m) if week[-1])

或许稍微快一点的方法是：

first_day,month_len = monthrange(y,m)
date_of_first_sun = 1+6-first_day
print sum(1 for x in range(date_of_first_sun,month_len+1,7))

Answer 6

您可以使用ISO周号来完成此操作：

from datetime import date
bom = date.today().replace(day=1)                 # first day of current month
eom = (date(bom.year, 12, 31) if bom.month == 12 else
       (bom.replace(month=bom.month + 1) - 1))    # last day of current month
_, b_week, _ = bom.isocalendar()
_, e_week, e_weekday = eom.isocalendar()
num_sundays = (e_week - b_week) + (1 if e_weekday == 7 else 0)

通常对于一周中的特定日期（1 =星期一，7 =星期日），计算结果为：

num_days = ((e_week - b_week) +
            (-1 if b_weekday > day else 0) +
            ( 1 if e_weekday >= day else 0))

Answer 7

import calendar

MONTH = 10    
sundays = 0
cal = calendar.Calendar()

for day in cal.itermonthdates(2012, MONTH):
    if day.weekday() == 6 and day.month == MONTH:
        sundays += 1

注意：以下是Calendar.itermonthdates的文档：

返回迭代器一个月。迭代器将产生datetime.date 价值观并将一直持续整整几周，因此它会产生在指定月份之外的日期。

这就是为什么需要day.month == MONTH

如果您希望工作日在0-6范围内，请使用day.weekday()，如果您希望它们在1-7范围内，请使用day.isoweekday()

计算当月的周日数

7 个答案: