我编写了一个简单的身份验证插件,它使用SOAP Web服务来检查用户名和密码。这很好。
我想在joomla的admin中有一些像SOAP密码这样的参数。所以我在xml中添加了params,它在admin中显示正常。当我试图获得它的价值时,我得到:
致命错误:在非对象上调用成员函数get()
所以我与其他身份验证进行比较,我的方式完全相同......我不明白为什么会这样。
以下是插件的代码:
public function __construct() {
$nusoap = JPATH_SITE . '/plugins/authentication/ers/nusoap/lib/nusoap.php';
if (! file_exists ( $nusoap )){
$response->error_message = "No such file";
return;
}
require_once ($nusoap);
}
function onUserAuthenticate($credentials, $options, &$response)
{
//Without defaults (the plugin crashes on the first get() bellow)
$webservice = $this->params->get('webservice', '');
$group = $this->params->get('group', '');
$whitepaw = $this->params->get('whitepaw', '');
JRequest::checkToken() or die( 'Invalid Token' );
// For JLog
$response->type = 'ERS SOAP Webservice';
// MyCompany does not like blank passwords (So does Joomla ;))
if (empty($credentials['password'])) {
$response->status = JAuthentication::STATUS_FAILURE;
$response->error_message = JText::_('JGLOBAL_AUTH_EMPTY_PASS_NOT_ALLOWED');
return false;
}
if (empty($credentials['username'])) {
$response->status = JAuthentication::STATUS_FAILURE;
$response->error_message = JText::_('Please enter a username');
return false;
}
// Add a user to joomla
function addJoomlaUser($name, $username, $password, $email, $group) {
$data = array(
"name"=>$name,
"username"=>$username,
"password"=>$password,
"password2"=>$password,
"email"=>$email,
"block"=>0,
"groups"=>array("1","2", $group) // the uer is added into the group "public" and "registered" as well as a group of the user's choice.
);
$user = clone(JFactory::getUser());
//Write to database
if(!$user->bind($data)) {
throw new Exception("Could not bind data. Error: " . $user->getError());
}
if (!$user->save()) {
throw new Exception("Could not save user. Error: " . $user->getError());
}
return $user->id;
}
// Pour supprimer le cache du web-service
ini_set('soap.wsdl_cache_enabled', 0);
// Nouveau Client SOAP
try {
// Nouvelle instance de la classe soapClient
$client = new SoapClient($webservice, array('trace' => true));
$username = $credentials['username'];
$password = $credentials['password'];
$result = $client->CheckLogin(array('whitepaw'=>$whitepaw, 'username'=>$username, 'password'=>$password));
if($result->isInDB){
$name = $result->fname.' '.$result->lname;
$email = $result->email;
$response->error_message = $username.'<br>'.$password.'<br>'.$name.'<br>'.$email."<br><br>".
"<b>Request :</b><br>".htmlentities($client->__getLastRequest())."<br><br>".
"<b>RESPONSE :</b><br>".htmlentities($client->__getLastResponse())."<br><br>";
if(!$result->email == '' || empty ($result)) {
//Todo: check if the user is already in joomla db
$user_id = addJoomlaUser($name, $username, $password, $email,$group);
$response->status = JAuthentication::STATUS_SUCCESS;
//for testing purposes
$response->error_message = $user_id;
} else {
$response->error_message = "The webservice did not return data".$email.'did you see it?';
}
} else {
$response->status = JAuthentication::STATUS_FAILURE;
$response->error_message = 'You do not have yet an account in <a href="http://my.ersnet.org">myers</a>. Please register.<br>';
$response->error_message .= $result->isInDB;
}
} catch (Exception $fault) {
$response->error_message = $fault->getMessage();
}
}
}
答案 0 :(得分:1)
由于你有自己的构造函数,你需要像这样调用父构造函数:
public function __construct(& $subject, $params = array()) {
$nusoap = JPATH_SITE . '/plugins/authentication/ers/nusoap/lib/nusoap.php';
if (! file_exists ( $nusoap )){
$response->error_message = "No such file";
return;
}
require_once ($nusoap);
// call the parent constructor
parent::__construct($subject, $params);
}
父构造函数是$this->params
对象设置的位置,因此如果不调用它,则永远不会设置$this->params
。这就是为什么你得到错误说params
不是一个对象。