Question

从表单中获取特定单词后。我想从数据库中的多个表中获得这样的结果。

function search(){
    $search = $this->input->post('searchword');
    $this->db->select('articles.title, articles.post');
    $this->db->select('files.name, files.desc');
    $this->db->select('news.title, news.post');
    $this->db->select('projects.title, projects.desc');
    $this->db->from('articles, files, news, projects');

    // I think problem is here
    $like = array('articles.title' => $search,'articles.post' => $search,
    'files.name' => $search,'files.desc' => $search,
    'news.title' => $search,'news.post' => $search,
    'projects.title' => $search, 'projects.desc' => $search);
    $this->db->like($like);


    return $this->db->get();

}

Answer 1

CI的加入是废话......

我总是会用连接创建一个合适的sql语句，然后执行它。

$query = $this->db->query("BUILD A PROPERLY JOINED QUERY!");

如果你自己无法做到这一点......在PHPMyAdmin或MySQL Workbench中构建查询，并确保得到你期望的结果。

另外，虽然我不是CI的Active Record的粉丝，但看看这篇文章可能会调整它正在创建的连接-http：//codeigniter.com/forums/viewthread/93198/

CodeIgniter - 搜索结果 - 如何从多个表中返回特定单词的搜索结果？

1 个答案: