Question

我想从名为tbl的表中的单个MySQL datetime列中选择一个起始列和一个结束列。有什么建议吗？

我的开始：

+---------------------+
|      date_time      |
+---------------------+
| 2012-03-05 10:15:52 |
| 2012-03-05 10:15:53 |
| 2012-03-05 10:15:54 |
+---------------------+

通缉结果：

+---------------------+---------------------+
|     start_time      |      end_time       |
+---------------------+---------------------+
| 2012-03-05 10:15:52 | 2012-03-05 10:15:53 |
| 2012-03-05 10:15:53 | 2012-03-05 10:15:54 |
+---------------------+---------------------+

Answer 1

SELECT   cur.date_time AS start_time, MIN(nxt.date_time) AS end_time
FROM     my_table AS cur JOIN my_table AS nxt ON nxt.date_time > cur.date_time
GROUP BY cur.date_time

在sqlfiddle上查看。

Answer 2

select end_time.date_time as [start], 
    (select 
    min(date_time) -- select smallest value from

    from da start_time --another table instance which i called start_time

        -- taking datetimes earlier than start 
    where start_time.date_time > end_time.date_time

    ) as [end]

from da end_time -- table instance with start time

--dont take last value (end time for that value will be null)
where 
    end_time.date_time < (select max(date_time) from da)

我的表：

TABLE [da]
Id  date_time
1   2012-03-05 10:15:52.000
2   2012-03-05 10:15:53.000
3   2012-03-05 10:15:54.000

我的结果：

start                   end
2012-03-05 10:15:52.000 2012-03-05 10:15:53.000
2012-03-05 10:15:53.000 2012-03-05 10:15:54.000

从单个日期时间列创建开始列和结束列

2 个答案: