Question

我正在尝试使用php中的json_decode解析json。它是一个url失败，任何人都可以告诉我它为什么失败并且在php中有json_decode的替代品吗？

这是我的代码

$url='https://espn.go.com/travel/sports/calendar/getList.json?&xhr=1&date=20121027&type=list&query=null&myTeams=';
$html = file_get_html($url);     
$json=json_decode($html,true);

// json在这里为空

Answer 1

file_get_html是PHP Simple HTML DOM Parser Not default PHP function应该是

 $html = file_get_contents($url);

请注意，返回的JSON有错误的UTF-8字符，可能编码错误

修复此问题

$url = 'http://espn.go.com/travel/sports/calendar/getList.json?&xhr=1&date=20121027&type=list&query=null&myTeams=';
$html = file_get_contents($url);
$json = preg_replace('/,\s*([\]}])/m', '$1', utf8_encode($html));
$json = json_decode($json);
echo "<pre>";
print_r($json);

输出

tdClass Object
(
    [nfb] => Array
        (
            [0] => stdClass Object
                (
                    [events] => Array
                        (
                            [0] => stdClass Object
                                (
                                    [id] => 265911
                                    [time] => 12:00 AM ET
                                    [sportId] => 23
                                    [link] => http://espn.go.com/ncf/team/_/name/
                                    [prevLink] => http://espn.go.com/ncf/preview?gameId=323010002
                                    [recapLink] => http://espn.go.com/ncf/recap?gameId=323010002
                                    [shortSport] => ncaa
                                    [homeId] => 2
                                    [awayId] => 245
                                    [homeScore] => -1

        ... So Many More

See Live Demo

json_decode在php中返回null

1 个答案: