我有一个触发器,用来测试一个打钟的个人是否在最后5分钟内打了他们的牌。如果他们没有他们的信息应该留给表clk_data,否则应该在日志表utl_logbook中创建一个记录,并且应该中止插入到clk_data。
当我运行良好的打孔时,插件的工作方式与宣传的一样。当它是一个糟糕的打击(在最后一拳的5分钟内)我得到以下错误:
SQL Error: ORA-20101: Too Soon
ORA-06512: at "TRUTRACK.INSERT_CLK_DATA", line 14
ORA-04088: error during execution of trigger 'TRUTRACK.INSERT_CLK_DATA'
交易已停止,但我没有在utl_logbook中记录它。
The trigger code:
create or replace
TRIGGER "INSERT_CLK_DATA"
BEFORE INSERT ON clk_data
FOR EACH row
BEGIN
DECLARE qty INTEGER := 0;
BEGIN
SELECT COUNT(*)
INTO qty
FROM clk_data
WHERE clk_time BETWEEN (:new.clk_time - 5/(24*60)) AND (:new.clk_time + 5/(24*60))
AND :new.payroll = clk_data.payroll;
IF qty > 0 THEN
INSERT INTO utl_logbook (time, source, message) VALUES (sysdate, 'INSERT_CLK_DATA', 'Clock punch within restricted window. Payroll ID:' || :new.payroll || ' Time: ' || :new.clk_time || ' Type: ' || :new.type);
RAISE_APPLICATION_ERROR(-20101, 'Too Soon');
END IF;
END;
END;
答案 0 :(得分:3)
当您可以使用pragma autonomous_transaction
时,这可能是极少数情况之一。它允许您在不影响主要事务的情况下提交。请谨慎使用。详细了解autonomous transactions和autonomous_transaction pragma
以下是一个例子:
-- our error logging table
create table tb_log(
msg varchar2(123)
)
/
-- our working table
create table tb_table(
col11 number
)
/
-- procedure that is going to log errors
NK@XE> create or replace procedure log_error(p_msg in varchar2)
2 is
3 pragma autonomous_transaction;
4 begin
5 insert into tb_log(msg)
6 values(p_msg);
7 commit;
8 end;
NK@XE> /
Procedure created.
NK@XE> create or replace trigger tr_tb_table
2 before insert on tb_table
3 for each row
4 begin
5 if mod(:new.col1, 2) != 0
6 then
7 log_error('Error!');
8 raise_application_error(-20000, 'Error has ocurred!');
9 end if;
10 end;
11 /
Trigger created.
NK@XE> select * from tb_log;
no rows selected
NK@XE> select * from tb_table;
no rows selected
NK@XE> insert into tb_table(col1) values(1);
insert into tb_table(col1) values(1)
*
ERROR at line 1:
ORA-20000: Error has ocurred!
ORA-06512: at "NK.TR_TB_TABLE", line 5
ORA-04088: error during execution of trigger 'NK.TR_TB_TABLE'
NK@XE> select * from tb_log;
MSG
--------------------------------------------------------------------------------
Error!
答案 1 :(得分:1)
@ nicholas-krasnov提供了解决方案,只是为了详细说明推理 - 你在触发器体中抛出异常:
RAISE_APPLICATION_ERROR(-20101, 'Too Soon');
导致回滚事务。有关详细信息,请访问:
http://psoug.org/reference/exception_handling.html
如果语句失败,Oracle将回滚到保存点。通常,只会丢失失败的SQL语句,而不是整个事务。但是,如果语句引发未处理的异常,则主机环境将确定回滚的内容。