Question

嘿，我搜索网了很长一段时间，但我找不到解决以下问题的方法：

在javafx中你有3个基本文件; controller-class，fxml文件和应用程序类。现在我想在控制器中做出反应点击按钮（效果非常好）并更改该点击的屏幕（你通常使用stage.setScreen（）），但我没有参考舞台（你可以在应用程序类中找到。）

应用程序示例：

public class JavaFXApplication4 extends Application {

@Override
public void start(Stage stage) throws Exception {
    Parent root = FXMLLoader.load(getClass().getResource("Sample.fxml"));

    Scene scene = new Scene(root);

    stage.setScene(scene);
    stage.show();
}

/**
 * The main() method is ignored in correctly deployed JavaFX application.
 * main() serves only as fallback in case the application can not be
 * launched through deployment artifacts, e.g., in IDEs with limited FX
 * support. NetBeans ignores main().
 *
 * @param args the command line arguments
 */
public static void main(String[] args) {
    launch(args);
}
}

FXML-样品：

<?xml version="1.0" encoding="UTF-8"?>

<?import java.lang.*?>
<?import java.util.*?>
<?import javafx.scene.*?>
<?import javafx.scene.control.*?>
<?import javafx.scene.layout.*?>

<AnchorPane id="AnchorPane" prefHeight="200.0" prefWidth="320.0"  xmlns:fx="http://javafx.com/fxml" fx:controller="javafxapplication4.SampleController">
  <children>
  <Button id="button" fx:id="nextScreen" layoutX="126.0" layoutY="90.0" onAction="#handleButtonAction" text="Next Screen" />
  <Label fx:id="label" layoutX="126.0" layoutY="120.0" minHeight="16.0" minWidth="69.0" />
  </children>
</AnchorPane>

控制器 - 样品：

public class SampleController implements Initializable {

@FXML
private Label label;

@FXML
private void handleButtonAction(ActionEvent event) {
    System.out.println("You clicked me!");
    label.setText("Hello World!");
    //Here I want to swap the screen!
}

@Override
public void initialize(URL url, ResourceBundle rb) {
    // TODO
}    
}

我会感谢任何帮助。

Answer 1

@FXML
private void handleButtonAction(ActionEvent event) {
    System.out.println("You clicked me!");
    label.setText("Hello World!");
    //Here I want to swap the screen!

    Stage stageTheEventSourceNodeBelongs = (Stage) ((Node)event.getSource()).getScene().getWindow();
    // OR
    Stage stageTheLabelBelongs = (Stage) label.getScene().getWindow();
    // these two of them return the same stage
    // Swap screen
    stage.setScene(new Scene(new Pane()));
}

Answer 2

我在进入Java并尝试解决同样的问题时发现了这个老问题。由于我希望场景能够记住开关之间的内容，所以我无法使用接受的答案，因为当在场景之间切换时，它会再次实例化它们（失去它们之前的状态）。

无论如何，接受的答案和answer to the similar question给了我一些关于如何在不失去状态的情况下切换场景的提示。主要思想是将场景的实例注入另一个控制器，这样控制器就不需要反复实例化一个新场景，但可以使用已经存在的实例（具有状态）。

所以这是实例化场景的主类：

public class Main extends Application {

    public static void main(String[] args) {
        launch(args);
    }

    @Override
    public void start(Stage primaryStage) throws Exception {
        // getting loader and a pane for the first scene. 
        // loader will then give a possibility to get related controller
        FXMLLoader firstPaneLoader = new FXMLLoader(getClass().getResource("firstLayout.fxml"));
        Parent firstPane = firstPaneLoader.load();
        Scene firstScene = new Scene(firstPane, 300, 275);

        // getting loader and a pane for the second scene
        FXMLLoader secondPageLoader = new FXMLLoader(getClass().getResource("secondLayout.fxml"));
        Parent secondPane = secondPageLoader.load();
        Scene secondScene = new Scene(secondPane, 300, 275);

        // injecting second scene into the controller of the first scene
        FirstController firstPaneController = (FirstController) firstPaneLoader.getController();
        firstPaneController.setSecondScene(secondScene);

        // injecting first scene into the controller of the second scene
        SecondController secondPaneController = (SecondController) secondPageLoader.getController();
        secondPaneController.setFirstScene(firstScene);

        primaryStage.setTitle("Switching scenes");
        primaryStage.setScene(firstScene);
        primaryStage.show();
    }
}

以下是两个控制器：

public class FirstController {

    private Scene secondScene;

    public void setSecondScene(Scene scene) {
        secondScene = scene;
    }

    public void openSecondScene(ActionEvent actionEvent) {
        Stage primaryStage = (Stage)((Node)actionEvent.getSource()).getScene().getWindow();
        primaryStage.setScene(secondScene);
    }
}

是的，第二个看起来是一样的（某些逻辑可能是共享的，但当前状态足以作为概念证明）

public class SecondController {

    private Scene firstScene;

    public void setFirstScene(Scene scene) {
        firstScene = scene;
    }

    public void openFirstScene(ActionEvent actionEvent) {    
        Stage primaryStage = (Stage)((Node)actionEvent.getSource()).getScene().getWindow();
        primaryStage.setScene(firstScene);
    }
}

Answer 3

您也可以尝试这样做。

public void onBtnClick(ActionEvent event) {
    try {
        FXMLLoader loader = new FXMLLoader(getClass().getResource("login.fxml"));
        Stage stage = (Stage) btn.getScene().getWindow();
        Scene scene = new Scene(loader.load());
        stage.setScene(scene);
    }catch (IOException io){
        io.printStackTrace();
    }

}

如何在控制器类的javafx应用程序中交换屏幕？

3 个答案: