我遇到了sql handler
的问题A SQLiteConnection object for database '/data/data/.../databases/queueManager' was leaked! Please fix your application to end transactions in progress properly and to close the database when it is no longer needed.
取自Androidhive教程并根据我的使用进行定制
表格看起来像
+ ----------------------------------------------------------- +
: DATABASE_ID : DATABASE_QID : DATABASE_QUEUE : DATABASE_DATE :
+ ----------------------------------------------------------- +
代码
DBQueue searchDBqid(int id) {
SQLiteDatabase db = this.getReadableDatabase();
String selectQuery = "SELECT * FROM " + TABLE_QUEUE + " WHERE " + DATABASE_QID + " = " + id;
Cursor cursornum = db.rawQuery(selectQuery, null);
int dk = cursornum.getCount();
cursornum.close();
if (dk >0) {
Cursor cursor = db.query(TABLE_QUEUE, new String[] { DATABASE_ID,
DATABASE_QID, DATABASE_QUEUE, DATABASE_DATE }, DATABASE_QID + "=?",
new String[] { String.valueOf(id) }, null, null, null, null);
if (cursor != null) cursor.moveToFirst();
DBQueue dbqueue = new DBQueue(Integer.parseInt(cursor.getString(0)),
cursor.getString(1), cursor.getString(2), cursor.getString(3));
return dbqueue;
}
db.close();
return null;
}
DBQueue getDBQueue(int id) {
SQLiteDatabase db = this.getReadableDatabase();
Cursor cursor = db.query(TABLE_QUEUE, new String[] { DATABASE_ID,
DATABASE_QID, DATABASE_QUEUE }, DATABASE_ID + "=?",
new String[] { String.valueOf(id) }, null, null, null, null);
if (cursor != null)
cursor.moveToFirst();
DBQueue dbqueue = new DBQueue(Integer.parseInt(cursor.getString(0)),
cursor.getString(1), cursor.getString(2), cursor.getString(3));
return dbqueue;
}
public String getAllqid() {
Time today = new Time(Time.getCurrentTimezone());
today.setToNow();
String selectQuery = "SELECT * FROM " + TABLE_QUEUE + " WHERE " + DATABASE_DATE + " = '" + today.format("%d %m %Y") + "'";
SQLiteDatabase db = this.getWritableDatabase();
Cursor cursor = db.rawQuery(selectQuery, null);
StringBuilder sb = new StringBuilder();
if (cursor.moveToFirst()) {
do {
if (sb.length() > 0) sb.append(',');
sb.append(cursor.getString(1));
} while (cursor.moveToNext());
}
String result = sb.toString();
return result;
}
public void deleteDatedDBQueue() {
Time today = new Time(Time.getCurrentTimezone());
today.setToNow();
String selectQuery = "SELECT * FROM " + TABLE_QUEUE + " WHERE " + DATABASE_DATE + " != '" + today.format("%d %m %Y") + "'"; ;
SQLiteDatabase db = this.getWritableDatabase();
Cursor cursor = db.rawQuery(selectQuery, null);
if (cursor.moveToFirst()) {
do {
db.delete(TABLE_QUEUE, DATABASE_ID + " = ?",
new String[] { String.valueOf(Integer.parseInt(cursor.getString(0))) });
} while (cursor.moveToNext());
}
db.close();
}
public int getDBQueueCount() {
String countQuery = "SELECT * FROM " + TABLE_QUEUE;
SQLiteDatabase db = this.getReadableDatabase();
Cursor cursor = db.rawQuery(countQuery, null);
cursor.close();
return cursor.getCount();
}
}
有人可以告诉我如何解决这个漏洞吗?
答案 0 :(得分:50)
完成后,应关闭每个Cursor
。传统的做法是:
Cursor cursor = db.query(...);
try {
// read data from the cursor in here
} finally {
cursor.close();
}
但是现在,使用try-with-resources,它可以更加简洁:
try (Cursor cursor = db.query(...)) {
// read data from the cursor in here
}
答案 1 :(得分:8)
您忘记多次关闭游标,确保在完成后始终关闭游标。
例如,第二个查询没有关闭光标,为了清楚起见,我已将其删除
如果您更改设计以使SQLiteDatabase
成为getDBQueue
,那么在getAllqid
,getDBQueueCount
和SQLiteOpenHelper
完成后,您也不会关闭SQLiteDatabase
单身然后你不需要关闭 DBQueue searchDBqid(int id) {
SQLiteDatabase db = this.getReadableDatabase();
String selectQuery = "SELECT * FROM " + TABLE_QUEUE + " WHERE " + DATABASE_QID + " = " + id;
Cursor cursornum = db.rawQuery(selectQuery, null);
int dk = cursornum.getCount();
cursornum.close();
if (dk >0) {
// TODO: Close this cursor!
Cursor cursor = db.query(TABLE_QUEUE, new String[] { DATABASE_ID,
DATABASE_QID, DATABASE_QUEUE, DATABASE_DATE }, DATABASE_QID + "=?",
new String[] { String.valueOf(id) }, null, null, null, null);
if (cursor != null) cursor.moveToFirst();
DBQueue dbqueue = new DBQueue(Integer.parseInt(cursor.getString(0)),
cursor.getString(1), cursor.getString(2), cursor.getString(3));
return dbqueue;
}
db.close();
return null;
}
并避免泄漏
{{1}}
答案 2 :(得分:1)
每次打开数据库(可读或可写)时,必须使用“.close();”释放使用内存资源的游标。在每个数据库函数的使用结束后 例如:
if (cursor != null) cursor.moveToFirst();
DBQueue dbqueue = new DBQueue(Integer.parseInt(cursor.getString(0)),
cursor.getString(1), cursor.getString(2), cursor.getString(3));
return dbqueue;
}
cursor.close();
db.close();
return null;
}
DBQueue getDBQueue(int id) {
SQLiteDatabase db = this.getReadableDatabase();
Cursor cursor = db.query(TABLE_QUEUE, new String[] { DATABASE_ID,
DATABASE_QID, DATABASE_QUEUE }, DATABASE_ID + "=?",
new String[] { String.valueOf(id) }, null, null, null, null);
if (cursor != null)
cursor.moveToFirst();
DBQueue dbqueue = new DBQueue(Integer.parseInt(cursor.getString(0)),
cursor.getString(1), cursor.getString(2), cursor.getString(3));
cursor.close();
db.close();
return dbqueue;
}
依旧...... !!
答案 3 :(得分:0)
第一次打开数据库并最后输入此代码。
@Override
protected void onDestroy() {
// TODO Auto-generated method stub
mdb.close();
super.onDestroy();
}