我正在创建一个包含向量的双重链接循环列表,我无法弄清楚如何修复我得到的两个NullPointerExceptions。它们都使用我的add方法,一个add方法在列表的末尾插入一个对象,另一个在给定的索引处插入对象。这是我的代码。
import java.util.Iterator;
import java.util.NoSuchElementException;
import java.util.Vector;
public class DList<T> implements ADTListInterface<T> {
private int size;
private int BUCKET;
private DListNode head;
private DListNode last;
public DList() {
head = new DListNode(null);
head.next = last;
head.prev = head;
BUCKET = 1;
}
public DList(int bucket){
if (bucket <= 0)
throw new IllegalArgumentException("Cannot have a bucket lower than 1");
this.BUCKET = bucket;
head = new DListNode(null);
head.next = last;
head.prev = head;
}
private class DListNode {
private Vector<T> item; //Line 29
private DListNode next; //Line 30
private DListNode prev;
public DListNode(T o) {
this(o, null, null);
}
public DListNode(T o, DListNode next, DListNode prev) {
item = new Vector<T>(BUCKET);
item.add(o);
this.next = next;
this.prev = prev;
}
public void add(T item) {
if (this.item.size() == this.item.capacity()) {
DListNode newNode = new DListNode(item, this.next, this);
this.next = newNode;
}
else {
insertAfter(item);
}
}
public void add(T item, int idx) {
if (this.item.size() == this.item.capacity()) {
DListNode newNode = new DListNode(this.item.elementAt(BUCKET), this.next, this);
this.next = newNode;
}
else {
this.item.add(idx, item);
}
}
public boolean remove(T o){
if (item.indexOf(o) != -1){
item.remove(o);
if (item.size() == 0){
this.prev.next = this.next;
this.next.prev = this.prev;
}
size--;
return true;
}
return false;
}
public void insertAfter(T item) {
next = new DListNode(item, next, prev);
next.next.prev = next;
}
public DListNode nth(int index) {
if (index == 1)
return this;
else if (index < 0 || next == null) {
throw new java.util.NoSuchElementException("No Such Element");
} else
return next.nth(index - 1);
}
}
@Override
public void add(T o) {
DListNode last = head;
while (last.item.size() >= BUCKET && last.next != head) {
last = last.next;
}
if (last.item.size() == BUCKET) { //Line 102
DListNode n = new DListNode(o, head, last);
head.prev.next = n;
head.prev = n;
size++;
} else {
last.item.add(o);
}
}
@Override
public void add(T o, int index) {
DListNode temp = head, testNext;
int count = 0;
while (count+1 <= index) {
count += temp.item.size();
temp = temp.next;
if (temp == head) {
throw new IndexOutOfBoundsException("Out Of Bounds!");
}
}
testNext = temp.next; //Line 126
temp.add(o, index);
if (testNext != temp.next)
size++;
}
}
我得到的两个错误是:
线程“main”java.lang.NullPointerException中的异常 在DList $ DListNode.access $ 0(DList.java:29) 在DList.add(DList.java:102) 在DListNodeDriver.main(DListNodeDriver.java:7)
线程“main”java.lang.NullPointerException中的异常 在DList $ DListNode.access $ 1(DList.java:30) 在DList.add(DList.java:126) 在DListNodeDriver.main(DListNodeDriver.java:6)
谢谢,任何帮助表示赞赏。
主要方法
import java.util.Iterator;
public class DListNodeDriver {
public static void main(String[] args) {
DList<String> students = new DList<String>();
students.add("Other", 1);
students.add("New", 3);
Iterator<String> t = students.iterator();
while (t.hasNext()) {
String temp = t.next();
StdOut.println("Student: " + temp);
}
}
}
import java.util.Iterator;
public class DListNodeDriver {
public static void main(String[] args) {
DList<String> students = new DList<String>();
students.add("Other");
students.add("New");
Iterator<String> t = students.iterator();
while (t.hasNext()) {
String temp = t.next();
StdOut.println("Student: " + temp);
}
}
}
答案 0 :(得分:1)
由于显而易见的原因,您的temp
为空。一步一步:
head.next
是null
。students.add("other",1);
- &gt;循环中的temp = temp.next
及其null
。类似的问题发生在students.add("other")
。
我会根据你的实现做这样的事情:
@Override
public void add(T o, int index) {
DListNode temp = head
int count = 0;
// < instead of <= because if index = size, your temp will be null otherwise.
// if index = 1 , you'll want to add after head. Watch out for index > size!
// It is an IndexOutOfBounds, index = size => add behind last element.
while (count+1 < index) {
count++;
if( temp.next == null ) { /*Handle that case */ }
else {temp = temp.next;}
//if (temp == head) {
// throw new IndexOutOfBoundsException("Out Of Bounds!");
//}
}
// temp should now be the element just before the index at which to insert.
// I'd do a temp.insertAfter( o );
/* DO YOUR ADDING HERE*/
}
答案 1 :(得分:0)
你知道容器的最大尺寸,你自己管理插入,我建议使用T []代替Vector。你可能期望更好的表现(没有锁定)和更明确的错误。
在下面的代码示例中,用参数化参数T
替换Objecthttp://fr.scribd.com/doc/81926911/37/The-Circular-Linked-List