DIV中的Ajax响应

Question

您好我想稍微修改下面的脚本，以便它将响应输出到div而不是警报，请参阅粗体部分。任何帮助表示赞赏！

function processResponse() {
    if (gateway.readyState == 4 && gateway.status == 200) {
        alert("Done loading!\n\nThe response from the PHP script was: "+gateway.responseText);
    }
}

Answer 1

如果div有id，请尝试这样的事情：

document.getElementById("divId").innerHTML = gateway.responseText;

Answer 2

function processResponse() { 
    if (gateway.readyState == 4 && gateway.status == 200) {
        document.getElementById("yourDiv").innerHTML = "php script was : " + gateway.responseText;
    } 
}

或者如果使用jquery

function processResponse() { 
    if (gateway.readyState == 4 && gateway.status == 200) {
        $("#youdivid").html("php script was : " + gateway.responseText);
    } 
}