Question

我有一个以下的类（只有部分，更多的类中的字段）

class Network{
public:
      string src_ip_;
      string alternative_src_ip_;
      array<unsigned char,6> mac_;
      string toString(){
           stringstream ss;
           ss << src_ip_ << SEPERATOR << alternative_src_ip_ << SEPERATOR ;
           return ss.str();
      }
}

我想在toString方法中添加格式化的mac（带:) 是否有一种简单的方法来采用我的printMac方法（通过generelize或通过编写新的方法），这将在＆lt;＆lt;＆lt;＆lt;运营商

void printMac(array<unsigned char, 6> mac) {
    printf("%02x:%02x:%02x:%02x:%02x:%02x\n", 
            (unsigned char) mac[0], (unsigned char) mac[1],
            (unsigned char) mac[2], (unsigned char) mac[3],
            (unsigned char) mac[4], (unsigned char) mac[5]);
}

Answer 1

使用IO manipulators：

std::ostringstream s;
unsigned char arr[6] = { 0, 14, 10, 11, 89, 10 };

s << std::hex << std::setfill('0');

for (int i = 0; i < sizeof(arr); i++)
{
    if (i > 0) s << ':';

    // Need to:
    //  - set width each time as it only
    //    applies to the next output field.
    //  - cast to an int as std::hex is for
    //    integer I/O
    s << std::setw(2) << static_cast<int>(arr[i]);
}

Answer 2

您可以使用sprintf替换printf的使用，然后使用它来实现运算符＆lt;＆lt;对于ostreams

void printMac(array<unsigned char, 6> mac, char (&out)[18]) {
    sprintf(out, "%02x:%02x:%02x:%02x:%02x:%02x", 
            (unsigned char) mac[0], (unsigned char) mac[1],
            (unsigned char) mac[2], (unsigned char) mac[3],
            (unsigned char) mac[4], (unsigned char) mac[5]);
}

std::ostream &operator<<(std::ostream &os, std::array<unsigned char, 6> mac) {
    char buf[18];
    printMac(mac, buf);
    return os << buf << '\n';
}

Answer 3

如果您想维护类似printf的代码，可以尝试Boost.Format。

ss << boost::format("%02x:%02x:%02x:%02x:%02x:%02x\n") % mac[0] % mac[1] % mac[2] % mac[3] % mac[4] % mac[5];

将格式化的mac地址写入stringstream

3 个答案: