Question

我对Rails有疑问。我的数据库中有一个没有主键的表，包含这些列 - person_id，year，salary。我的问题是当我想编辑其中一个薪水时。我无法理解如何做到这一点。那是我的代码：

工资控制员：

def index
    @salaries = Salary.all
end

def edit
    @salary = Salary.find_by_person_id_and_year(params[:person_id], params[:year])
    @people = Person.all
end

index.html.erb

<% @salaries.each do |salary| %>
    <b><%= salary.person.Name %></b>
    <b><%= salary.Year %></b>
    <b><%= salary.Amount %></b>
    <%= link_to "Edit", edit_salary_path(salary.person_id, salary.year)%>
<% end %>

所以，我把它添加到我的routes.rb：

get 'salaries/index', :to => 'salaries#index',:as => 'salaries'
get 'salaries/:person_id/:year', :to => 'salaries#show', :as => 'salary'   
get 'salaries/new/:person_id/:year', :to => 'salaries#edit', :as => 'new_salary'
get 'salaries/edit/:person_id/:year', :to => 'salaries#edit', :as => 'edit_salary'
put 'salaries/:person_id/:year', :to => 'salaries#update'
post 'salaries/:person_id/:year', :to => 'salaries#create'
delete 'salaries/:person_id/:year', :to => 'salaries#destroy'

但是我的_form.html.erb中有这些错误消息：“此行上的nil：NilClass的未定义方法`join'：＆lt;％= form_for（@salary）do | f | ％GT;

def edit
    @person_id = params[:person_id]
    @year = params[:year]
    @salary = Salary.find_by_person_id_and_year(params[:person_id], params[:year])
    @people = People.all
end

def update
    @people = People.all
    @salary = Salary.new(params[:salary])
    if @salary.save
        flash[:success] = "Successfully edited salary"
        redirect_to salaries_path
    else
        @title = "Edit salary"
        render 'edit'
    end
end

_form.html.erb

<%= form_for(@salary, :url => salaries_path(:person_id => @person_id, :year => @year)) do |f|   %>

Answer 1

Rails路由会自动查找ID，因此您需要自定义路由。

例如，在config / routes.rb中代替resources :salaries尝试类似：

get 'salaries/index', :to => 'salaries#index',:as => 'salaries'
get 'salaries/edit/:person_id/:year', :to => 'salaries#edit', :as => 'edit_salaries'
put 'salaries/:person_id/:year', :to => 'salaries#update'

根据需要使用其他路线，例如：

get 'salaries/index', :to => 'salaries#index',:as => 'salaries'
get 'salaries/:person_id/:year', :to => 'salaries#show', :as => 'salary'
get 'salaries/new/:person_id/:year', :to => 'salaries#edit', :as => 'new_salary'
get 'salaries/edit/:person_id/:year', :to => 'salaries#edit', :as => 'edit_salary'
put 'salaries/:person_id/:year', :to => 'salaries#update'
post 'salaries/:person_id/:year', :to => 'salaries#create'
delete 'salaries/:person_id/:year', :to => 'salaries#destroy'

形式：

form_for(@salary, :url => salary_path(:person_id => X, :year => Y)) do |f|

Answer 2

如果您可以在工资表中添加其他ID列，则可以使用标准导轨功能，例如

(in app/models/person.rb)

class Person
  has_many :salaries
  has_one :current_salary, :class_name => "Salary", 
          :conditions => lambda { {:year => Time.now.year} }
  # outer curlies are for the lambda, inner curlies are for it to return a hash
end

(in config/routes.rb)


resources :people do
  resources :salaries
end

然后使用ID

进行普通访问

没有主键的Rails表

2 个答案: