有没有人知道如何在PL / SQL存储过程中生成.Net DateTime.Ticks,而Oracle数据库中没有.Net程序集?
我在.Net中有一个服务,将DateTime.Ticks值存储在[Oracle数据库]列中。 现在我必须创建一个存储过程来创建类似的信息,但我必须匹配该特定列中的.Net标记。
答案 0 :(得分:2)
使用Oracle函数计算自纪元(0001年1月1日午夜12点00分)以来的秒数,忽略闰秒,乘以10e6(千万)得到滴答。
找到.NET时间刻度的定义here。
答案 1 :(得分:2)
我想出了整个算法并构建了一个函数。它就像一个魅力......
这就是:
CREATE OR REPLACE FUNCTION GLOBAL.Get_DotNet_Ticks
(
inTimestamp IN TIMESTAMP
) RETURN NUMBER AS
-- **********************************************************************************
-- File name: Get_DotNet_Ticks
-- Original Author: Roberto Lopes
-- Creation Date: October 2012
-- Description: Returns the number of ticks for the provided timestamp, based
-- on the Microsoft .Net algorithm
-- **********************************************************************************
BeginDate TIMESTAMP := TO_TIMESTAMP('0001-01-03', 'YYYY-MM-DD'); --.Net Ticks are counted starting from this date
BEGIN
RETURN (EXTRACT(DAY FROM(inTimestamp - BeginDate)) * 86400000 + (TO_NUMBER(TO_CHAR(inTimestamp, 'SSSSSFF3'))))*10000;
END Get_DotNet_Ticks;
答案 2 :(得分:1)
我不熟悉Oracle PL / SQL,但是以下DateToTicks()
C#函数(直接取自Mono的开源DateTime实现)揭示了给定DateTime值的各个组件时如何计算滴答的详细信息。也许它有所帮助。
祝你好运!
public const long TicksPerDay = 864000000000L;
private static readonly int[] daysmonth = { 0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
private static readonly int[] daysmonthleap = { 0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31 };
private static int AbsoluteDays(int year, int month, int day) {
int[] days;
int temp = 0, m = 1;
days = (IsLeapYear(year) ? daysmonthleap : daysmonth);
while( m < month )
temp += days[m++];
return ((day - 1) + temp + (365 * (year - 1)) + ((year - 1) / 4) - ((year - 1) / 100) + ((year - 1) / 400));
}
public static bool IsLeapYear(int year) {
if( year < 1 || year > 9999 )
throw new ArgumentOutOfRangeException();
return ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0);
}
internal static bool CalculateTicks(int days, int hours, int minutes, int seconds, int milliseconds, out long result) {
// there's no overflow checks for hours, minutes, ...
// so big hours/minutes values can overflow at some point and change expected values
int hrssec = (hours * 3600); // break point at (Int32.MaxValue - 596523)
int minsec = (minutes * 60);
long t = ((long)(hrssec + minsec + seconds) * 1000L + (long)milliseconds);
t *= 10000;
result = 0;
bool overflow = false;
// days is problematic because it can overflow but that overflow can be
// "legal" (i.e. temporary) (e.g. if other parameters are negative) or
// illegal (e.g. sign change).
if( days > 0 ) {
long td = TicksPerDay * days;
if( t < 0 ) {
long ticks = t;
t += td;
// positive days -> total ticks should be lower
overflow = (ticks > t);
} else {
t += td;
// positive + positive != negative result
overflow = (t < 0);
}
} else if( days < 0 ) {
long td = TicksPerDay * days;
if( t <= 0 ) {
t += td;
// negative + negative != positive result
overflow = (t > 0);
} else {
long ticks = t;
t += td;
// negative days -> total ticks should be lower
overflow = (t > ticks);
}
}
if( overflow ) {
return false;
}
result = t;
return true;
}
public static bool DateToTicks (int year, int month, int day, int hour, int minute, int second, int millisecond, out long result) {
return CalculateTicks(AbsoluteDays(year, month, day), hour, minute, second, millisecond, out result);
}
答案 3 :(得分:0)
Ticks property是long
,因此您需要使用合适的Oracle类型:'Number'