如何用sql xml中的变量替换指针值?

时间:2012-09-25 17:37:58

标签: sql xml sql-server-2008

我需要编写WHILE循环并将变量传递给xml查询:

鉴于这个逻辑:

DECLARE @count INT = 0;
DECLARE @pointer INT = 0;
DECLARE @pointer_str varchar(100);

DECLARE @MyXML XML
SET @MyXML = '<SampleXML>
                <Colors>
                <Color1>White</Color1>
                <Color2>Blue</Color2>
                <Color3>Black</Color3>
                <Color4 Special="Light">Green</Color4>
                <Color5>Red</Color5>
                </Colors>
                <Colors>
                <Color1>White</Color1>
                <Color2>Blue</Color2>
                <Color3>Black</Color3>
                <Color4 Special="Light">Green</Color4>
                <Color5>Red</Color5>
                </Colors>
            </SampleXML>'

SET @count = 
    (
        SELECT
            a.b.value('count(/SampleXML/Colors)', 'int')
        FROM 
            @MyXML.nodes('data') a(b)
    )

WHILE @count < @pointer
    BEGIN   
        SELECT
            a.b.value('Colors[' + @pointer + ']/Color1[1]','varchar(10)') AS Color1
        FROM 
            @MyXML.nodes('SampleXML') a(b);

        SELECT @pointer = @pointer + 1;
    END 

我试图在SELECT语句中获取以下变量来解析XML,但是我收到以下错误:

The argument 1 of the XML data type method "value" must be a string literal.

另外,当我传递文字值'1'时,我看不到选择是在循环内运行的。有人可以帮帮我吗?

1 个答案:

答案 0 :(得分:1)

  

我需要编写WHILE循环并将变量传递给xml查询:

在XML.value()方法中,您可以将变量varName称为sql:variable("@varName")

关于您的问题,我认为您正在尝试在XML中的Color1个节点中提取文本。以下SQL执行此操作:

DECLARE @count INT = 0;
DECLARE @pointer INT = 0;
DECLARE @pointer_str varchar(100);

DECLARE @MyXML XML
SET @MyXML = '<SampleXML>
        <Colors>
        <Color1>White</Color1>
        <Color2>Blue</Color2>
        <Color3>Black</Color3>
        <Color4 Special="Light">Green</Color4>
        <Color5>Red</Color5>
        </Colors>
        <Colors>
        <Color1>Green</Color1>
        <Color2>Blue</Color2>
        <Color3>Black</Color3>
        <Color4 Special="Light">Green</Color4>
        <Color5>Red</Color5>
        </Colors>
    </SampleXML>'

SELECT @count = count(a.b.query('.')) FROM @MyXml.nodes('/SampleXML/Colors') as a(b)

SELECT
    a.b.value('.', 'varchar(10)')
FROM 
    @MyXML.nodes('/SampleXML/Colors/Color1') a(b);

它将输出生成为

----------
White
Green

(2 row(s) affected)