Question

我想通过PHP从REST XML文件中获取方法。我有本地REST文件，格式为：

SimpleXMLElement Object
(
    [doc] => SimpleXMLElement Object
        (
        )

    [resources] => SimpleXMLElement Object
        (
            [@attributes] => Array
                (
                    [base] => https://**url**
                )

            [resource] => Array
                (
                    [0] => SimpleXMLElement Object
                        (
                            [@attributes] => Array
                                (
                                    [path] => xml/{accesskey}/project
                                )

                            [param] => SimpleXMLElement Object
                                (
                                    [@attributes] => Array
                                        (
                                            [name] => accesskey
                                            [style] => template
                                            [type] => xs:string
                                        )

                                )

                            [method] => SimpleXMLElement Object
                                (
                                    [@attributes] => Array
                                        (
                                            [id] => getAllProjects
                                            [name] => GET
                                        )

                                    [response] => SimpleXMLElement Object
                                        (
                                            [representation] => SimpleXMLElement Object
                                                (
                                                    [@attributes] => Array
                                                        (
                                                            [mediaType] => application/xml; charset=utf-8
                                                        )

                                                )

                                        )

                                )
... and so on

我有以下代码，但它只返回第一个方法名称：

$file="application.wadl";
$xml = simplexml_load_file($file);

foreach($xml->resources[0]->resource->method->attributes() as $a => $b) {
    echo $b,"\n";
}

我想提取所有这些，而不仅仅是第一个。怎么做？

Answer 1

不是循环遍历一个元素的属性，而是需要遍历所有具有相同名称的元素。由于SimpleXML的神奇之处，这很简单：

foreach($xml->resources->resource->method as $method) {
    echo $method['id'],"\n";
}

当跟随另一个运算符时，与->resources一样，SimpleXML假设您只想要具有该名称的第一个元素。但是如果你循环，它会给你们每一个，作为一个SimpleXML对象。

编辑：看起来XML的嵌套意味着您需要某种形式的递归（您需要查看$xml->resources->resource->resource->resource->method等）。

这样的事情（未经测试的例子）？

function get_methods($base_url, $node)
{
    $all_methods = array();     

    // Child resources: build up the path, and recursively fetch all methods
    foreach ( $node->resource as $child_resource )
    {
        $child_url = $base_url . '/' . (string)$child_resource['path'];

        $all_methods = array_merge(
            $all_methods, 
            get_methods($child_url, $child_resource)
        );
    }

    // Methods in this resource: add to array directly
    foreach ( $node->method as $method )
    {
        $method_url = $base_url . '/' .(string)$method['id'];
        $all_methods[$method_url] = (string)$method['id'];
    }

    return $all_methods;
}

print_r( get_methods('/', $xml->resources) );

顺便说一下，print_r并不总能为您提供SimpleXML对象的最佳视图，因为它们实际上是非PHP代码的包装器。请改为this simplexml_dump() function。

从REST调用中获取方法

1 个答案: