如何将在终端中运行的Java应用程序转换为具有UI的桌面应用程序？

Question

我知道他们有很多不同的方法可以做到这一点，但我很擅长使用终端，并希望继续创建用户界面和桌面应用程序！我写了一个非常俗气和杂乱的“数字游戏”，并希望它能够在带有按钮和所有爵士乐的小程序中运行！

public static void gameStart()  {
    System.out.println("Welcome to the Game of Awesome V1.2");
    System.out.println("-------------------------------------");
    spin();
}

public static void spin()   {

    int spinNum = (int)(10*Math.random());
    Scanner input = new Scanner(System.in);
    Scanner input2 = new Scanner(System.in);
    System.out.println("type a number between 1 and 10:");
    int guessNum = input.nextInt();

    if(guessNum > 10)   {
        System.out.println(guessNum + " is greater than 10 you fool!");
                    spin();
    }else if(guessNum < 1)  {
        System.out.println(guessNum + " is less than 1 you fool!");
                    spin();
    }else   {

                System.out.println("\nSweet, looks like you chose [" + guessNum + "], good luck...");
                System.out.println("\ntype \"s\" to spin and \"quit\" to, quit...");
                String run = input2.nextLine();
            switch (run.toLowerCase()) {
                case "s":
                    System.out.println("\nyou spun [" + spinNum + "] and guessed [" + guessNum + "]!");
                    if(guessNum == spinNum) {
                        win();
                        askPlay();
                    }else   {
                            lose();
                            askPlay();
                    }
                    break;
                case "quit":
                    System.out.println("See ya later!");
                    System.out.println();
                    System.exit(0);
                    break;
                default:
                    System.out.println("shit, you broke it! Luckily, I can fix this.");
                    askPlay();
                    System.out.println();
                    break;
            }
            }
}

public static void askPlay()    {

        Scanner input = new Scanner(System.in);
        System.out.println("\nWanna play again? (Type \"yes\" or \"no\")");
        String decideSpin = input.nextLine();

    switch (decideSpin.toLowerCase()) {
        case "yes":
            spin();
            break;
        case "no":
            System.out.println("\nI know it's a crappy game, thanks for playing though!");
            System.out.println();
            System.exit(0);
            break;
        default:
            System.out.println("\nI'm sorry,\nI was made by a lazy "
            + "programmer and can only understand \"yes\" or \"no\"..");
            askPlay();
            break;
    }
}

public static void win()    {
    System.out.println("\nWINNER: you won this insanley stupid game, of awesome! Be proud, winner. (:");
}

public static void lose()   {
    System.out.println("\nLOOOOOSSSSSEEEERRRR: yep, you stand with the majority with this loss.");
}

我该怎么做？

Answer 1

我建议您先阅读Swing Trail

你需要了解的另一件事是Swing是事件驱动的，不像它倾向于顺序运行的控制台程序

Answer 2

嗯，很简单：开始学习一些Java的GUI，我会推荐这两个中的一个：

• Swing

• SWT

Answer 3

绝对开始学习Swing。这是标准的Java GUI框架。

Answer 4

考虑在Processing（Java Library / Applet）中运行它。这可能是最简单的最简单的方法。如果您愿意，甚至可以将其导出为应用程序。干杯！