我知道如何检测双击和双指触摸事件,但我如何将这些结合起来反应,以便有人需要用两根手指双击?
默认情况下,Android长按可以作为第二种点击形式,但我特意寻找双指双击。
答案 0 :(得分:14)
我想要一个简单且可重复使用的界面,它可以侦听两个手指双击并且表现得像GestureDetector。所以你可以像这样使用它(所有剪切和粘贴可运行的代码):
public class Example extends Activity {
SimpleTwoFingerDoubleTapDetector multiTouchListener = new SimpleTwoFingerDoubleTapDetector() {
@Override
public void onTwoFingerDoubleTap() {
// Do what you want here, I used a Toast for demonstration
Toast.makeText(Example.this, "Two Finger Double Tap", Toast.LENGTH_SHORT).show();
}
};
// Override onCreate() and anything else you want
@Override
public boolean onTouchEvent(MotionEvent event) {
if(multiTouchListener.onTouchEvent(event))
return true;
return super.onTouchEvent(event);
}
}
我创建了SimpleTwoFingerDoubleTapDetector。 (这是一个很长的名字,但它是描述性的。你可以将它重命名为你想要的任何东西。)将这个新文件保存在你的项目中或作为一个库:
public abstract class SimpleTwoFingerDoubleTapDetector {
private static final int TIMEOUT = ViewConfiguration.getDoubleTapTimeout() + 100;
private long mFirstDownTime = 0;
private boolean mSeparateTouches = false;
private byte mTwoFingerTapCount = 0;
private void reset(long time) {
mFirstDownTime = time;
mSeparateTouches = false;
mTwoFingerTapCount = 0;
}
public boolean onTouchEvent(MotionEvent event) {
switch(event.getActionMasked()) {
case MotionEvent.ACTION_DOWN:
if(mFirstDownTime == 0 || event.getEventTime() - mFirstDownTime > TIMEOUT)
reset(event.getDownTime());
break;
case MotionEvent.ACTION_POINTER_UP:
if(event.getPointerCount() == 2)
mTwoFingerTapCount++;
else
mFirstDownTime = 0;
break;
case MotionEvent.ACTION_UP:
if(!mSeparateTouches)
mSeparateTouches = true;
else if(mTwoFingerTapCount == 2 && event.getEventTime() - mFirstDownTime < TIMEOUT) {
onTwoFingerDoubleTap();
mFirstDownTime = 0;
return true;
}
}
return false;
}
public abstract void onTwoFingerDoubleTap();
}
首先,关于Android的一些注意事项(一键式) GestureDetector :
onDoubleTap()
事件使用ViewConfiguration中的标准超时值。我指的是同一时间。onDoubleTap()
和onDoubleTapEvent()
。
onDoubleTap()
仅在第二次敲击手指发生事件时触发。onDoubleTapEvent()
会针对每个操作触发:向下,向上移动。关于 SimpleTwoFingerDoubleTapDetector 的几点说明:
onTwoFingerDoubleTap()
。 最后说明: 您可以轻松更改此操作,使其行为类似于OnTouchListener:
更改SimpleTwoFingerDoubleTapDetector的定义:
public abstract class SimpleTwoFingerDoubleTapListener implements OnTouchListener {
添加新的类变量:
private View mFirstView;
更改ACTION_DOWN
案例:
case MotionEvent.ACTION_DOWN:
if(mFirstDownTime == -1 || mFirstView != v || hasTimedOut(event.getEventTime())) {
mFirstView = v;
reset(event.getDownTime());
}
break;
在mFirstView
案例中传递ACTION_UP
:
onTwoFingerDoubleTap(mFirstView);
最后,更改onTwoFingerDoubleTap()
方法以反映点击了哪个视图:
public abstract void onTwoFingerDoubleTap(View v);
答案 1 :(得分:1)
这是我创建的双击侦听器,用于检测双指双击。
使用的变量:
private GestureDetector gesture;
private View.OnTouchListener gestureListener;
boolean click1 = false;
boolean click2 = false;
long first = 0;
long second = 0;
在活动的onCreate()
中注册触摸事件:
gesture = new GestureDetector(getApplicationContext(), new SimpleOnGestureListener(){
public boolean onDown(MotionEvent event) {
return true;
}
});
gestureListener = new View.OnTouchListener() {
@Override
public boolean onTouch(View v, MotionEvent event) {
return gesture.onTouchEvent(event);
}
};
活动内onCreate()
之外:
@Override
public boolean onTouchEvent(MotionEvent event) {
try {
int action = event.getAction() & MotionEvent.ACTION_MASK;
//capture the event when the user lifts their fingers, not on the down press
//to make sure they're not long pressing
if (action == MotionEvent.ACTION_POINTER_UP) {
//timer to get difference between clicks
Calendar now = Calendar.getInstance();
//detect number of fingers, change to 1 for a single-finger double-click, 3 for a triple-finger double-click, etc.
if (event.getPointerCount() == 2) {
if (!click1) {
//if this is the first click, then there hasn't been a second
//click yet, also record the time
click1 = true;
click2 = false;
first = now.getTimeInMillis();
} else if (click1) {
//if this is the second click, record its time
click2 = true;
second = now.getTimeInMillis();
//if the difference between the 2 clicks is less than 500 ms (1/2 second)
//Math.abs() is used because you need to be able to detect any sequence of clicks, rather than just in pairs of two
//(e.g. click1 could be registered as a second click if the difference between click1 and click2 > 500 but
//click2 and the next click1 is < 500)
if (Math.abs(second-first) < 500) {
//do something!!!!!!
} else if (Math.abs(second-first) >= 500) {
//reset to handle more clicks
click1 = false;
click2 = false;
}
}
}
}
} catch (Exception e){
}
return true;
}