Question

出于某种原因\ u009a被发送到xmlhttp.responseText而不是\ u0161，我不知道为什么。我希望š显示在文本框中，而是改为发送单个字符介绍人。我有什么想法可以解决这个问题吗？

主页代码：

function loadDoc()
{
   var xmlhttp;

   // code for IE7+, Firefox, Chrome, Opera, Safari
   if (window.XMLHttpRequest)
   {
      xmlhttp=new XMLHttpRequest();
   }
   // code for IE6, IE5
   else
   {
      xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
   }

   xmlhttp.onreadystatechange=function()
   {
      if (xmlhttp.readyState==4 && xmlhttp.status==200)
      {
         alert(xmlhttp.responseText);
         var a = JSON.parse(xmlhttp.responseText);
         document.getElementById("textbox").value=a.first;
         document.getElementById("textbox2").value=a.second;
         document.getElementById("textbox3").value=a.third;
         document.getElementById("textbox4").value=a.fourth;
         document.getElementById("textbox5").value=a.fifth;
         document.getElementById("textbox6").value=a.sixth;
      }
   }

   xmlhttp.open("GET","loadTextBox.php?id=4",true);
   xmlhttp.send();
}

loadTextBox.php代码：

<?php
header("Content-type: application/json");

---Placeholder for correct DB login info---

$result = $mysql->query(---Placeholder for correct SQL query---);

while ($row = $result->fetch_object())
{
   $queryResult[] = $row->present_tense;
}
$textboxValue = $queryResult[0];
$textboxValue2 = $queryResult[1];
$textboxValue3 = $queryResult[2];
$textboxValue4 = $queryResult[3];
$textboxValue5 = $queryResult[4];
$textboxValue6 = $queryResult[5];
echo json_encode(array('first'=>utf8_encode($textboxValue),'second'=>
utf8_encode($textboxValue2),'third'=>utf8_encode($textboxValue3),'fourth'=>
utf8_encode($textboxValue4),'fifth'=>utf8_encode($textboxValue5),'sixth'=>
utf8_encode($textboxValue6)));
?>

Answer 1

添加行$ mysql-＆gt;查询（“SET CHARACTER SET'utf8'”）;在连接到DB之后和SQL查询之前的loadTextBox.php里面，用utf8_encode删除行修复它。

转义单个字符介绍人而不是实际字符

1 个答案: