无法在后http请求中获取http JSON响应

时间:2012-09-12 14:57:08

标签: android json post request response

我尝试在下面的代码中接收http响应:

public void httpRes (){
try {
    HttpClient client = new DefaultHttpClient();
    String postURL = "http://validate.jsontest.com/";
    HttpPost post = new HttpPost(postURL);
        List<NameValuePair> params = new ArrayList<NameValuePair>();
        params.add(new BasicNameValuePair("user", "kris"));
        params.add(new BasicNameValuePair("pass", "xyz"));
        UrlEncodedFormEntity ent = new UrlEncodedFormEntity(params, HTTP.UTF_8);
        post.setEntity(ent);
        HttpResponse responsePOST = client.execute(post);
        HttpEntity resEntity = responsePOST.getEntity();
        if (resEntity != null) {
            Log.i("RESPONSE",EntityUtils.toString(resEntity));
        }
} catch (Exception e) {
    e.printStackTrace();
}}

出错 -

LogCat日志:

09-12 21:48:58.099: INFO/RESPONSE(28485): {
        "error": "No JSON to validate. Please post JSON to validate via the json parameter.",
        "validate": false
        }

我试图接收来自GET requsets的响应 - 一切都很好,但是当我尝试POST请求各种各样的POST代码时 - 我无法得到答案!问题是什么?需要帮助。

我也试过了:

Map<String, String> comment = new HashMap<String, String>();
comment.put("password", "password");
comment.put("avatar", "httpssssssss");

String json = new GsonBuilder().create().toJson(comment, Map.class);
HttpResponse response = makeRequest("http://validate.jsontest.com/", json);
//Log.w(TAG, EntityUtils.toString(response));
try {
    HttpEntity entity = response.getEntity();
    InputStream is = entity.getContent();
    String sss= convertStreamToString(is);
    Log.w("SSSSSSSSSSSSSSSSSS", sss);
} catch (Exception ex) {
    Log.w("Exception exxx", ex);
}
public static HttpResponse makeRequest(String uri, String json) {
        try {
            HttpPost httpPost = new HttpPost(uri);
            httpPost.setEntity(new StringEntity(json));
            httpPost.setHeader("Accept", "application/json");
            httpPost.setHeader("Content-type", "application/json");
            return new DefaultHttpClient().execute(httpPost);
        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
        } catch (ClientProtocolException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
        return null;
    }

private static String convertStreamToString(InputStream is) {

        BufferedReader reader = new BufferedReader(new InputStreamReader(is));
        StringBuilder sb = new StringBuilder();
        String line = null;
        try {
            while ((line = reader.readLine()) != null) {
                sb.append((line + "\n"));
            }
        } catch (IOException e) {
            e.printStackTrace();
        } finally {
            try {
                is.close();
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
        return sb.toString();
    }

那么,问题是什么?

3 个答案:

答案 0 :(得分:1)

http://validate.jsontest.com拒绝POST请求,除非Content-Type标头设置为application/x-www-form-urlencoded

答案 1 :(得分:0)

通过GET你的代码行

HttpPost httpPost = new HttpPost(uri);

应该是

HttpPost httpPost = new HttpPost(uri+"?json="+json);

我觉得你不需要下面三行。

通过POST你需要像这样传递json参数。

params.add(new BasicNameValuePair("json", json));

假设json是包含json数据的变量。

您可以在浏览器中测试GET方法,如http://validate.jsontest.com/?json= {validate:true}

答案 2 :(得分:-1)

您需要将有效的json发布到网址http://validate.jsontest.com/以验证它。你正在做的是基本上发送一个post请求到url,它不是json格式。 您必须将其编码为json,然后将其发送到验证网址。