以下是我从MYSQL数据库中搜索日期范围的代码。 我能够搜索日期并显示表格标题(产品说明,新建或自己和日期),但它不显示数据库中的任何结果?
有关如何编辑代码以便显示所选日期范围内结果的任何想法?
<?php
if(!isset($_POST['find']))
{
?>
<form method = "post" action = "<?php echo $_SERVER['PHP_SELF'];?>">
<table width = "450" align = "center">
<tr>
<td><b><i>Please enter date in the field below (i.e. 11-09-2012)</i></b></td>
</tr>
<tr>
<td>
From :
<input type = "text" name = "small">
To :
<input type = "text" name = "large"></td>
</tr>
<tr>
<td align = "center">
<input type = "submit" name = "find" value = "SEARCH">
<input type = "reset" value = "CLEAR FORM">
</td>
</tr>
</table>
</form>
<?php
}
else
{
$small = trim($_POST['small']);
$large = trim($_POST['large']);
$connection = mysql_pconnect("localhost", "user_name", "password") or die("Connection failed. ".myslq_error());
mysql_select_db("stock") or die("Unable to select db. ".mysql_error());
//Add 1 to the upper range, $large, else it won't make it inclusive
$query = "SELECT * FROM main_stock WHERE curr_timestamp BETWEEN DATE_FORMAT(curr_timestamp,'%".$small."') AND DATE_FORMAT(curr_timestamp, '%".($large+1)."') ORDER BY curr_timestamp";
$result = mysql_query($query) or die(mysql_error());
echo "<table width = '500' align = 'center'>";
echo "<tr><b>";
echo "<td>Product Description</td>";
echo "<td>New or Own?</td>";
echo "<td>Date</td>";
echo "</b></tr>";
while($record = mysql_fetch_object($result))
{
echo "<tr>";
echo "<td>".$record->product_desc."</td>";
echo "<td>".$record->newown."</td>";
$year_part_of_date = explode('-', $record->curr_timestamp);
echo "<td>".$year_part_of_date[0]."</td>";
//if you want the full date replace the $year_part_of_date[0] with $record->date
echo "</tr>";
}
echo "</table>";
}
?>
答案 0 :(得分:0)
我猜你的查询无效。
假设curr_timestamp
是格式为YYYY-MM-DD HH:MM:SS
的MySQL日期时间字段,您需要将输入更改为此格式以便于比较。如果您可以详细说明有用的$small
和$large
格式。
您可能希望查询采用此格式
SELECT * FROM main_stock
WHERE curr_timestamp BETWEEN '$small_formatted' AND '$large_formatted'
ORDER BY curr_timestamp ASC
使用$small_formatted
$large_formatted
和date('Y-m-d H:i:s', $input_timestamp)
进行了适当格式化的时间
答案 1 :(得分:0)
else
。SELECT *
)。始终指定列列表。YYYY-MM-DD
)。我假设curr_timestamp
是YYYY-MM-DD
。mysql_
函数deprecated。我没有对此进行过测试,但这解决了我上面列出的问题:
<?php
if(isset($_POST['find']))
{
$link = mysqli_connect("localhost", "user_name", "password", "stock");
if (mysqli_connect_error()) {
die('Connect Error (' . mysqli_connect_errno() . ') ' . mysqli_connect_error());
}
$stmt = mysqli_prepare($link, 'SELECT * FROM main_stock WHERE curr_timestamp ' .
"BETWEEN DATE_FORMAT(?, '%m-%d-%Y') " .
"AND DATE_FORMAT(?, '%m-%d-%Y') ORDER BY curr_timestamp");
mysqli_bind_param($stmt, 'ss', $_POST['small'], $_POST['large']) or die(mysqli_error($dbh));
$result = mysqli_stmt_execute($stmt) or die(mysqli_error($link));
echo "<table width = '500' align = 'center'>";
echo "<tr><b>";
echo "<td>Product Description</td>";
echo "<td>New or Own?</td>";
echo "<td>Date</td>";
echo "</b></tr>";
while($record = mysqli_fetch_assoc($result)) {
echo "<tr>";
echo "<td>" . $record[product_desc] . "</td>";
echo "<td>" . $record[newown] . "</td>";
$year_part_of_date = explode('-', $record[curr_timestamp]);
echo "<td>".$year_part_of_date[0]."</td>";
//if you want the full date replace the $year_part_of_date[0] with $record->date
echo "</tr>";
}
echo "</table>";
mysqli_close($link);
}
else
{
?>
<form method = "post" action = "<?php echo $_SERVER['PHP_SELF'];?>">
<table width = "450" align = "center">
<tr>
<td><b><i>Please enter date in the field below (i.e. 11-09-2012)</i></b></td>
</tr>
<tr>
<td>
From :
<input type = "text" name = "small">
To :
<input type = "text" name = "large"></td>
</tr>
<tr>
<td align = "center">
<input type = "submit" name = "find" value = "SEARCH">
<input type = "reset" value = "CLEAR FORM">
</td>
</tr>
</table>
</form>
<?php
}
?>