我有一个NSDate变量。从该变量中,我如何能够在视图中显示持续更新的秒表?
我已经尝试了[NSTimer scheduledTimerWithTimeInterval]
,但无法让它发挥作用,但也怀疑这是理想的做法。
答案 0 :(得分:3)
NSTimer
有什么问题?
- (void)startTimer {
[NSTimer scheduledTimerWithTimeInterval:1/30.0f
target:self
selector:@selector(timerFired:)
userInfo:[NSDate date]
repeats:YES];
}
- (void)timerFired:(NSTimer *)timer {
NSDate *startDate = timer.userInfo;
NSTimeInterval secondsPassed = -[startDate timeIntervalSinceNow];
// Update your label here.
}
答案 1 :(得分:2)
尝试此
- (void)updateTimer
{
static NSInteger counter = 0;
[stopWatchLabel setText:[NSString stringWithFormat:@"Counter: %i", counter++]];
}
- (IBAction)onStartPressed:(id)sender {
startDate = [[NSDate date]retain];
// Create the stop watch timer that fires every 10 ms
stopWatchTimer = [NSTimer scheduledTimerWithTimeInterval:1.0/10.0
target:self
selector:@selector(updateTimer)
userInfo:nil
repeats:YES];
}
您必须将IBAction连接到一个按钮,并将stopWatchLabel连接到界面构建器中的UILabel。
答案 2 :(得分:1)
我试过这个,它的工作
[NSTimer scheduledTimerWithTimeInterval:1 target:self selector:@selector(timerCallback) userInfo:nil repeats:YES];
-(void)timerCallback{
NSDate *date=[NSDate date];
NSLog(@"%@",date);
}
将timeInterval参数更新为你想要的,并在视图中显示它(我刚刚打印了日志);
我收到了这个日志:
2012-09-12 18:04:11.252 S[19550:f803] 2012-09-12 12:34:11 +0000
2012-09-12 18:04:12.170 S[19550:f803] 2012-09-12 12:34:12 +0000
2012-09-12 18:04:13.170 S[19550:f803] 2012-09-12 12:34:13 +0000
2012-09-12 18:04:14.170 S[19550:f803] 2012-09-12 12:34:14 +0000
2012-09-12 18:04:15.170 S[19550:f803] 2012-09-12 12:34:15 +0000
2012-09-12 18:04:16.170 S[19550:f803] 2012-09-12 12:34:16 +0000
2012-09-12 18:04:17.170 S[19550:f803] 2012-09-12 12:34:17 +0000
2012-09-12 18:04:18.170 S[19550:f803] 2012-09-12 12:34:18 +0000
2012-09-12 18:04:19.171 S[19550:f803] 2012-09-12 12:34:19 +0000
2012-09-12 18:04:20.170 S[19550:f803] 2012-09-12 12:34:20 +0000
2012-09-12 18:04:21.170 S[19550:f803] 2012-09-12 12:34:21 +0000