我从控制器返回了这个Json:
public ActionResult VerifyApp(string recurrence)
{
List<foo> item = schedulingProxy.CheckApp(recurrence);
return Json(item, JsonRequestBehavior.AllowGet);
}
我认为我有这张表:
<div class="table">
<table id="thids" class="bg">
<thead>
<tr>
<th>
Date
</th>
<th>
Time
</th>
<th>
Slot
</th>
<th>
</th>
</tr>
</thead>
<tbody>
@foreach (var item in conflictList)
{
<tr id="@item.ID">
<td>
@Html.DisplayFor(modelItem => item.ResourceFName)
</td>
<td>
@Html.DisplayFor(modelItem => item.ResourceLName)
</td>
<td>
@Html.DisplayFor(modelItem => item.ResourceSlot)
</td>
<td>
@Html.DisplayFor(modelItem => item.reason)
</td>
</tr>
}
</tbody>
</table>
我也在视图的顶部添加了这个:
@{
var conflictList =new List<Mavi.Domain.Model.contactThread>();
}
我在我的Jquery中有这个Axaj调用:
function ChkAvailable() {
pairString = pairString + newObj.ToString() + "]";
var requrl = '@Url.Action("VerifyAppointment", "Scheduling", null, Request.Url.Scheme, null)';
$.ajax({
type: "POST",
url: requrl,
data: { recurrence: pairString },
success: function (data) {
//returned List<foo>
}
});
}
如何将我返回的JSon对象中的值添加到conflictList中?或者更好..我怎样才能填充我的表格?
答案 0 :(得分:4)
如果我理解你的话,你只需要将新的html内容附加到你的表中,如下所示:
...
success: function (data) {
for(var el in data)
{
$("#thids").find("tbody")
.append($("<tr>").append($("<td>").text(el.ResourceFName))/*and so on*/);
}
}
...