我需要使用上一个日期的最新日期在MySQL中减去两行:
起始表:
Stock Date Price
GOOG 2012-05-20 402
GOOG 2012-05-21 432
APPL 2012-05-20 553
APPL 2012-05-21 590
FB 2012-05-20 40
FB 2012-05-21 34
这是结果表:
Stock Date Price Change
GOOG 2012-05-21 30
APPL 2012-05-21 37
FB 2012-05-21 -6
现在我每个公司只有两个日期,但如果你的查询可以处理任意数量的日期,奖金就会增加。
答案 0 :(得分:3)
我所做的是获得两个单独的查询以获得每个股票的最大日期和最短日期。试试这个,
SELECT maxList.stock,
maxList.Date,
(maxlist.Price - minlist.Price) totalPrice
FROM
(
SELECT a.*
FROM tableName a INNER JOIN
(
SELECT Stock, MAX(date) maxDate
FROM tableName
GROUP BY Stock
) b ON a.stock = b.stock AND
a.date = b.maxDate
) maxList INNER JOIN
(
SELECT a.*
FROM tableName a INNER JOIN
(
SELECT Stock, MIN(date) minDate
FROM tableName
GROUP BY Stock
) b ON a.stock = b.stock AND
a.date = b.minDate
) minList ON maxList.stock = minList.stock
更新1
看到你的最后一句话:Right now I just have two dates per company, but bonus upvotes if your query can handle any number of dates.
如果你有这样的记录怎么办?
FB 2012-05-20 40
FB 2012-05-21 34
FB 2012-05-22 42
它的结果是什么?
答案 1 :(得分:1)
我知道这已经得到了解答,但问题引起了我的兴趣,所以我想我会试一试。
我假设您可能希望看到任何两个连续日期之间的差异。
所以对于以下数据:
GOOG 2012-09-07 42.34
GOOG 2012-09-06 44.56
GOOG 2012-09-01 44.32
FB 2012-09-07 17.82
FB 2012-08-05 12.98
你会得到:
GOOG 2012-09-07 2012-09-06 -2.22
GOOG 2012-09-06 2012-09-01 0.24
FB 2012-09-07 2012-08-05 4.84
我为此写的查询是:
SELECT t1.Stock, t1.Date AS CurrentDate, oldDate.Date AS OldDate, (t1.Price - oldDate.Price) AS PriceChange
FROM MP_StockTable t1
JOIN (SELECT t2.Stock, t2.Date AS date1, (SELECT MAX(t3.Date) FROM MP_StockTable t3 WHERE t3.Date < t2.Date AND t3.Stock = t2.Stock GROUP BY t3.Stock) AS date2
FROM MP_StockTable t2) AS StockDates ON StockDates.Stock = t1.Stock AND StockDates.date1 = t1.Date
JOIN MP_StockTable oldDate ON oldDate.Stock = t1.Stock AND oldDate.Date = StockDates.date2
内联表基本上计算每行最接近的上一个日期。因此,对于上面的数据,生成的表将是这样的:
GOOG 2012-09-07 2012-09-06
GOOG 2012-09-06 2012-09-01
GOOG 2012-09-01 NULL
FB 2012-09-07 2012-08-05
FB 2012-08-05 NULL
然后我们使用该表中的两个日期来获得两个价格点。
注意:我正在SQLServer中进行测试,所以如果需要对mySql进行一些调整,那就道歉了(自从使用mySql以来已经有好几年了,所以我忘记了差异)。