我在一个项目中工作。我试图从使用以下代码创建的会话中获取用户名: -
GetCurrentUserInfo.java
package servlet;
import java.io.IOException;
import java.io.ObjectOutputStream;
import java.io.OutputStream;
import java.util.Vector;
import javax.servlet.ServletConfig;
import javax.servlet.ServletContext;
import javax.servlet.ServletException;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
public class GetCurrentUserInfo extends HttpServlet
{
ServletContext contx = null;
public void init(ServletConfig config) throws ServletException
{
contx = config.getServletContext();
}
public void doPost(HttpServletRequest req, HttpServletResponse res) throws ServletException, IOException
{
try
{
OutputStream outer = res.getOutputStream();
ObjectOutputStream oos = new ObjectOutputStream(outer);
String userName = (String) req.getSession().getAttribute("username");
oos.writeChars(userName);
oos.flush();
oos.close();
}
catch (Throwable e)
{
e.printStackTrace();
}
}
}
Calling.js
function getUserInfo()
{
var userInfoHttp;
if (window.XMLHttpRequest)
{
userInfoHttp = new XMLHttpRequest()
}
else if (window.ActiveXObject)
{
userInfoHttp = new ActiveXObject("Microsoft.XMLHTTP")
}
userInfoHttp.open("POST", "GetCurrentUserInfo", false);
userInfoHttp.setRequestHeader("Content-Type", "application/x-www-form-urlencoded");
userInfoHttp.onreadystatechange = function ()
{
if (userInfoHttp.readyState == 4)
{
if (userInfoHttp.status == 200)
{
var res = TrimString(userInfoHttp.responseText);
alert(res);
}
}
}
userInfoHttp.send(null);
isAnnotationUpdate = false;
}
我知道我正在获取带有一些额外字符的userName: - “ w s @ s . c o m” 实际上我的userName只是s@s.com。
答案 0 :(得分:0)
我认为有两件事可以解决您的编码问题
首先使用OutputStreamWriter并为其赋予编码值
OutputStream stream = response.getOutputStream();
OutputStreamWriter writer = new OutputStreamWriter(stream, "UTF-8");
String userName=(String)req.getSession().getAttribute("username");
writer.write(userName);
writer.flush();
然后确保您的回复具有正确的编码
response.setCharacterEncoding("UTF-8");
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<强>更新强>
在原始答案中我忘了其他的东西。将响应Object的ContentTyoe设置为text / plain,因为您实际上正在返回纯文本字符
response.setContentType("text/plain");