Question

我有类别列表。我需要排除2,3行的类别列表。我们可以通过使用Criteria和Restriction来实现休眠吗？

Answer 1

你的问题有点不清楚。假设“Category”是根实体而“2,3”是id（或类别的某些属性的值），您可以使用以下内容排除它们：

Criteria criteria = ...; // obtain criteria from somewhere, like session.createCriteria() 
criteria.add(
  Restrictions.not(
     // replace "id" below with property name, depending on what you're filtering against
    Restrictions.in("id", new long[] {2, 3})
  )
);

DetachedCriteria可以做同样的事情。

Answer 2

 Session session=(Session) getEntityManager().getDelegate();
        Criteria criteria=session.createCriteria(RoomMaster.class);
//restriction used or inner restriction ...
        criteria.add(Restrictions.not(Restrictions.in("roomNumber",new String[] { "GA8", "GA7"})));
        criteria.setResultTransformer(Criteria.DISTINCT_ROOT_ENTITY);
        List<RoomMaster> roomMasters=criteria.list();

Answer 3

对于Hibernate 5.2版本以后的新条件：

CriteriaBuilder criteriaBuilder = getSession().getCriteriaBuilder();
CriteriaQuery<Comment> criteriaQuery = criteriaBuilder.createQuery(Comment.class);

List<Long> ids = new ArrayList<>();
ids.add(2L);
ids.add(3L);

Root<Comment> root = getRoot(criteriaQuery);
Path<Object> fieldId = root.get("id");
Predicate in = fieldId.in(ids);
Predicate predicate = criteriaBuilder.not(in);

criteriaQuery
        .select(root)
        .where(predicate);

List<Comment> list = getSession()
        .createQuery(criteriaQuery)
        .getResultList();

如何通过在Hibernate中使用限制和标准来实现“不在”？

3 个答案: