Question

问题说明了一切。当我打印属性时，它是：

cn: WF-008-DAM-PS

代码段是：

private void searchGroup() throws NamingException {
    NamingEnumeration<SearchResult> searchResults = getLdapDirContext().search(groupDN, "(objectclass=groupOfUniqueNames)", getSearchControls());
    String searchGroupCn = getCNForBrand(m_binder.getLocal("brandId"), m_binder.getLocal("brandName"));
    Log.info(searchGroupCn);
    while (searchResults.hasMore()) {
        SearchResult searchResult = searchResults.next();
        Attributes attributes = searchResult.getAttributes();
        Attribute groupCn = attributes.get("cn");
        if(groupCn != null) {
            Log.info(groupCn.toString());               
        }
    }
}

我怎样才能获得WF-008-DAM-PS的值，即没有关键部分？问候。

Answer 1

解决方案是：

Attribute groupCn = attributes.get("cn");
String value = groupCn.get();

Answer 2

调用getValue()方法或getValue(int)方法。

Answer 3

常规

让我们说我们有：

Attributes attributes; Attribute a = attributes.get("something");

if(a.size() == 1)

然后您可以使用a.get()或a.get(0)来获取唯一值

if(a.size() > 1)

遍历所有值：

for ( int i = 0 ; i < a.size() ; i++ ) { Object currentVal = a.get(i); // do something with currentVal }

如果你在这里使用a.get()，它将只返回第一个值，因为它的内部实现（在BasicAttribute中）如下所示：

public Object get() throws NamingException { if (values.size() == 0) { throw new NoSuchElementException("Attribute " + getID() + " has no value"); } else { return values.elementAt(0); } }

两种方法（get(int)和get()）都会抛出NamingException。

实际示例
（当Attribute实例有多个值时）

LdapContext ctx = new InitialLdapContext(env, null); Attributes attributes = ctx.getAttributes("", new String[] { "supportedSASLMechanisms" }); System.out.println(attributes); // {supportedsaslmechanisms=supportedSASLMechanisms: GSSAPI, EXTERNAL, DIGEST-MD5} Attribute a = atts.get("supportedsaslmechanisms"); System.out.println(a); // supportedSASLMechanisms: GSSAPI, EXTERNAL, DIGEST-MD5 System.out.println(a.get()); // GSSAPI for (int i = 0; i < a.size(); i++) { System.out.print(a.get(i) + " "); // GSSAPI EXTERNAL DIGEST-MD5 }

Answer 4

这有效：（在获取属性值之前检查属性是否存在）

            Attributes attributes = searchResult.getAttributes();
            Attribute mail = attributes.get("mail");
            if (mail != null)
               {
                   System.out.println(" Mail-id value from LDAP :"+mail.get());
               }

如何从javax.naming.directory.Attribute中提取值

4 个答案: