我想将java对象编组为xml字符串。 因此,我获得了一个模式,我可以从中生成JAXB类。 有一个set方法(对应于模式中的hexbinary类型的元素),我必须设置一个字符串。 字符串大小约为2566。 通过setter方法将数据设置到对象后,我调用marshaller传递stringWriter参数。
但是在打印stringWriter时,我发现它被截断了。我没有看到整个2566个字符。
有什么问题?有什么想法吗?
感谢名单!
更新
我想我发现了这个问题。我必须找到合适的标题,因为我的问题推理错误!问题如下: 我的架构中有一个“hexbinary”元素。生成的类具有相应的set / get方法。要设置值,我使用了apache commons包的HexEncodeString方法,并意识到marshaller在hexbinary标签中显示36383639字符串“hi”,其实际的Hex编码是6869 :(因此,问题是编组后的xml有一个标签使用大于原始字符的字符数的值,而不是像我之前想象的那样被截断!
感谢 Blaise Doughan 的代码。我修改了它并重现了这个问题。
首先是一个示例模式:
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<xs:schema version="1.0" xmlns:xs="http://www.w3.org/2001/XMLSchema">
<xs:complexType name="Root">
<xs:sequence>
<xs:element name="string" type="xs:string" minOccurs="0"/>
<xs:element name="a" type="xs:hexBinary" minOccurs="0"/>
</xs:sequence>
</xs:complexType>
</xs:schema>
有了这个,我生成了ObjectFactory类和Root类。 我不得不修改ObjectFactory类以包含JAXBElement,以便我可以将它传递给Marshaller。有了这些,我参加了Blaise Doughan的Demo课程并将其修改为:
public class Demo {
public static void main(String[] args) throws Exception {
JAXBContext jc = JAXBContext.newInstance(Root.class);
// The object factory
ObjectFactory objFactory = new ObjectFactory();
Root root = new Root();
String str = new String("hi");
String val = Hex.encodeHexString(str.getBytes());
root.setString(str);
root.setArr(val.getBytes());
System.out.println("val="+val);
System.out.println("getString ="+root.getString());
System.out.println("getArr="+new String(root.getArr()));
// Marshal the object to a StringWriter
Marshaller marshaller = jc.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
marshaller.setProperty(Marshaller.JAXB_ENCODING, "UTF-8");
marshaller.setProperty(Marshaller.JAXB_SCHEMA_LOCATION, "http://www.example.com/schema.xsd");
StringWriter stringWriter = new StringWriter();
marshaller.marshal(objFactory.createRoot(root),stringWriter);
// marshaller.marshal(root, stringWriter);
// Convert StringWriter to String
String xml = stringWriter.toString();
System.out.println(xml);
// Unmarshal the XML and check length of long String
Unmarshaller unmarshaller = jc.createUnmarshaller();
Root unmarshalledRoot = (Root) unmarshaller.unmarshal(new StringReader(xml));
System.out.println(root.getString().length());
System.out.println(root.getString());
System.out.println(new String(root.getArr()).length());
System.out.println(new String(root.getArr()));
}
}
我得到的输出是:
val=6869
getString =hi
getArr=6869
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<ns3:Root xsi:schemaLocation="http://www.example.com/schema.xsd" xmlns:ns3="http://example.com/root" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<string>hi</string>
<arr>36383639</arr>
</ns3:Root>
Exception in thread "main" javax.xml.bind.UnmarshalException: unexpected element (uri:"http://example.com/root", local:"Root"). Expected elements are (none)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext.handleEvent(UnmarshallingContext.java:631)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.Loader.reportError(Loader.java:236)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.Loader.reportError(Loader.java:231)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.Loader.reportUnexpectedChildElement(Loader.java:105)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext$DefaultRootLoader.childElement(UnmarshallingContext.java:1038)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext._startElement(UnmarshallingContext.java:467)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallingContext.startElement(UnmarshallingContext.java:448)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.SAXConnector.startElement(SAXConnector.java:137)
at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.startElement(AbstractSAXParser.java:501)
at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.scanStartElement(XMLNSDocumentScannerImpl.java:400)
at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl$NSContentDriver.scanRootElementHook(XMLNSDocumentScannerImpl.java:626)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl$FragmentContentDriver.next(XMLDocumentFragmentScannerImpl.java:3103)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl$PrologDriver.next(XMLDocumentScannerImpl.java:922)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentScannerImpl.next(XMLDocumentScannerImpl.java:648)
at com.sun.org.apache.xerces.internal.impl.XMLNSDocumentScannerImpl.next(XMLNSDocumentScannerImpl.java:140)
at com.sun.org.apache.xerces.internal.impl.XMLDocumentFragmentScannerImpl.scanDocument(XMLDocumentFragmentScannerImpl.java:511)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:808)
at com.sun.org.apache.xerces.internal.parsers.XML11Configuration.parse(XML11Configuration.java:737)
at com.sun.org.apache.xerces.internal.parsers.XMLParser.parse(XMLParser.java:119)
at com.sun.org.apache.xerces.internal.parsers.AbstractSAXParser.parse(AbstractSAXParser.java:1205)
at com.sun.org.apache.xerces.internal.jaxp.SAXParserImpl$JAXPSAXParser.parse(SAXParserImpl.java:522)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal0(UnmarshallerImpl.java:200)
at com.sun.xml.internal.bind.v2.runtime.unmarshaller.UnmarshallerImpl.unmarshal(UnmarshallerImpl.java:173)
at javax.xml.bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl.java:137)
at javax.xml.bind.helpers.AbstractUnmarshallerImpl.unmarshal(AbstractUnmarshallerImpl.java:194)
at example.Demo.main(Demo.java:43)
为什么arr标记为36383639而不是6869?
答案 0 :(得分:1)
新答案
在示例代码中,val
是str.getBytes()
的hexBinary表示形式。但是,您在arr
属性上设置的值是十六进制编码的字符串中的字节。
String str = new String("hi");
String val = Hex.encodeHexString(str.getBytes());
root.setString(str);
root.setArr(val.getBytes());
我相信你的意思是:
String str = new String("hi");
String val = Hex.encodeHexString(str.getBytes());
root.setString(str);
root.setArr(str.getBytes());
将产生以下输出
val=6869
getString =hi
getArr=hi
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<root xsi:schemaLocation="http://www.example.com/schema.xsd" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<string>hi</string>
<a>6869</a>
</root>
换句话说
String str = new String("hi");
System.out.print("String: " + str);
System.out.println(" hexBinary: " + Hex.encodeHexString(str.getBytes()));
String val = Hex.encodeHexString(str.getBytes());
System.out.print("String: " + val);
System.out.println(" hexBinary: " + Hex.encodeHexString(val.getBytes()));
将输出:
String: hi hexBinary: 6869
String: 6869 hexBinary: 36383639
原始回答
我无法重现您所看到的问题。我使用String
大小的500000
。以下是我的尝试(这个样本适合你?)。是否有可能截断是由于您正在将长字符串写入控制台?
<强>演示强>
package forum12146217;
import java.io.*;
import javax.xml.bind.*;
public class Demo {
public static void main(String[] args) throws Exception {
JAXBContext jc = JAXBContext.newInstance(Root.class);
// Build a long String
StringBuilder stringBuilder = new StringBuilder();
for(int x=0; x<500000; x++) {
stringBuilder.append("a");
}
Root root = new Root();
root.setString(stringBuilder.toString());
System.out.println(root.getString().length());
// Marshal the object to a StringWriter
Marshaller marshaller = jc.createMarshaller();
marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
marshaller.setProperty(Marshaller.JAXB_ENCODING, "UTF-8");
marshaller.setProperty(Marshaller.JAXB_SCHEMA_LOCATION, "http://www.example.com/schema.xsd");
StringWriter stringWriter = new StringWriter();
marshaller.marshal(root, stringWriter);
// Convert StringWriter to String
String xml = stringWriter.toString();
//System.out.println(xml);
// Unmarshal the XML and check length of long String
Unmarshaller unmarshaller = jc.createUnmarshaller();
Root unmarshalledRoot = (Root) unmarshaller.unmarshal(new StringReader(xml));
System.out.println(unmarshalledRoot.getString().length());
}
}
<强>根强>
package forum12146217;
import javax.xml.bind.annotation.XmlRootElement;
@XmlRootElement
public class Root {
private String string;
public String getString() {
return string;
}
public void setString(String string) {
this.string = string;
}
}
<强>输出强>
500000
500000