Question

我有三个字符串，如

string a = "[ERROR] = any thing And [ID] > 20 And [NAME] like Varun";
string b = "[AGE] < 60 Or [ERROR] like Exception And [ID] > 20 And [NAME] like Varun And [ERROR] = any thing ";
string c = "[ID] > 20 And`enter code here` [NAME] like Varun And [ERROR] = any thing";

我想删除从[ERROR]开始到下一个运算符的字符串，如And / Or .....

我想要答案

string a = "[ID] > 20 And [NAME] like Varun";
string b = "[AGE] < 60 And [ID] > 20 And [NAME] like Varun";
string c = "[ID] > 20 And [NAME] like Varun";

如何删除.. ???

Answer 1

如果你对正则表达式不满意（我假设你不是），你可以使用这个伪代码：

将字符串拆分为单词（以空格分隔）
扫描单词列表，如果它等于[ERROR]，则跳过所有单词，直至下一个单词，以[开头，以]结尾

如果单词以[开头并以]结尾，则将其添加到输出中以及所有后续单词不以[开头并以]。

public static String FilterString(string value)
{
  string[] lsWords = value.Split(' ');
  StringBuilder lsbBuilder = new StringBuilder();

  bool lbIncluding = true;

  foreach(String lsWord in lsWords)
  {
    if (lsWord.StartsWith("[") && lsWord.EndsWith("]"))
       lbIncluding = (lsWord != "[ERROR]");

    if (lbIncluding)
    {
      if (lsbBuilder.Length > 0) lsbBuilder.Append(' ');
      lsbBuilder.Append(lsWord);
    }
  }

  return lsbBuilder.ToString();
}

...

string a = "[ERROR] = any thing And [ID] > 20 And [NAME] like Varun";
string b = "[AGE] < 60 Or [ERROR] like Exception And [ID] > 20 And [NAME] like Varun And [ERROR] = any thing ";
string c = "[ID] > 20 And`enter code here` [NAME] like Varun And [ERROR] = any thing";

a = FilterString(a);
b = FilterString(b);
c = FilterString(c);

这是输出：

[ID] > 20 And [NAME] like Varun
[AGE] < 60 Or [ID] > 20 And [NAME] like Varun And
[ID] > 20 And`enter code here` [NAME] like Varun And

这并没有摆脱ANDS / ORS等等，你需要自己做那个，但这应该给你一个很好的起点。

从字符串中删除列及其值

1 个答案: