Question

我有两张表readysale和ordersale。我想得到两张桌子的总和。表的列像 t1=pid,branch,quantity 和 t2=pid,branch,quantity。我需要分支列中所有分支的列表，并显示readysale,ordersale的总和数量。有些分店他们没有准备或订购销售，但它应该在列表中显示为0。

Answer 1

这将从两个表联合在一起的表的总数量按分支分组：

select sales.branch, sum(sales.quantity) as quantity
from (
    select branch, quantity
    from readysale
    union
    select branch, quantity
    from ordersale
) as sales
group by sales.branch

Answer 2

select sum(u.quantity) as total, u.branch 
from (
    select quantity, branch 
    from readysale
    union
    select quantity, branch 
    from ordersale
    ) as u
group by u.branch

编辑：

然后

select u.itemcode, u.branch, sum(u.ordersaleqty), sum(u.readysaleqty)
from (
        select itemcode, branch, 0 as ordersalqty, quantity as readysaleqty 
        from readysale
        union
        select itemcode, branch, quantity as ordersalqty, 0 as readysaleqty  
        from ordersale
        ) as u
group by u.itemcode, u.branch

或使用完整的外部联接

  select 
    coalesce(r.itemcode, o.itemcode), 
    coalesce(r.branch, o.branch),
    sum (r.quantity) as readysaleqty,
    sum (o.quantity) as ordersaleqty
  from readysale r
  full outer join ordersale o on o.branche = r.branch
  group by coalesce(r.itemcode, o.itemcode), coalesce(r.branch, o.branch);

总结了两个专栏

2 个答案: