Question

我有一个页脚模板，它有一个输入并提交电子邮件订阅。每页都使用页脚。订阅成功后，它将重定向回当前页面。但是，我发现我传递一个字符串值来指示当前页面是什么。为Play 2.0应用程序设置页脚模板的最佳方法是什么？

footer.scala.html

@(page: String)
<div id="footer">
    <div class="input-append">
        <form action="@routes.ApplicationController.saveSubscription(page)"
                                method="post">
        <input type="text" name="emailAddress" placeholder="Your Email" />
        <input class="btn" type="submit" value="Subscribe" />
        </form>
    </div> <!-- /input-append -->  
</div> <!-- /footer -->

ApplicationController.java

public class ApplicationController extends Controller {
    public static Result saveSubscription(String page) {
        ..........
        flash("success", "success message");
        if (page.equals("page1")) {
            return redirect(routes.ApplicationController.page1());
        } else if (page.equals("page2")) {
            return redirect(routes.ApplicationController.page2());
        } 
    }
}

page1.scala.html

@main("Page 1") {
    <div>
    <p>page 1</p>
    </div>
    @footer("page1")
}

page2.scala.html

@main("Page 2") {
    <div>
    <p>page 2</p>
    </div>
    @footer("page2")
}

编辑1

我关注@virtualeyes但似乎从未调用过subscribe.js。这是新设置。

main.scala.html

<html>
    <head>
        <script type="text/javascript" src="@routes.Assets.at("javascripts/jquery.min.js")"></script>
    <script type="text/javascript" src="@routes.Assets.at("javascripts/vendor/jquery.validate.min.js")"></script>
    <script src="@routes.Assets.at("javascripts/main.js")" type="text/javascript"></script>
    <script src="@routes.Assets.at("javascripts/subscribe.js")" type="text/javascript"></script>

    </head>
    <body>
       @footer()
    </body>
</html>

footer.scala.html

<div id="footer">
    <div class="input-append">                  
      <form id="_form" action="@routes.ApplicationController.simpleSubscription()">
        <input type="text" name="emailAddress" placeholder="Your Email" />
        <input id="_process" class="btn" type="submit" value="Subscribe" />
      </form>
    </div> <!-- /input-append -->  
</div> <!-- /footer -->

路由

POST    /subscribe  controllers.ApplicationController.simpleSubscription()

现在我收到了他的错误： 找不到行动对于请求'GET /subscribe?emailAddress=fdsaf%40rte.com'

我不确定是否因为删除了method =“post”。如果我把它放回去，那么结果将返回但会重定向到/ subscribe页面。我还在subscribe.js上设置了一个断点，但似乎根本没有调用它。

编辑2 - 工作

在我为subscribe.coffee改变了一点并摆脱了main.coffee后，现在它正在工作。

subscribe.coffee

$('#_process').click (e) ->
  e.preventDefault()

  isValid = $('#_form').validate().form()
  if isValid
    $('#_process').spin()
    $.ajax
      type: "POST"
      url:  $('#_form').attr('action')
      data: $('#_form').serialize()
      success: (data) ->
        $('#_status > div').removeClass('alert-error').addClass('alert-success')
        $('#_status > div').html( data )
        $('#_status').fadeIn()
        fade = () -> $('#_status').fadeOut('slow')
        setTimeout fade, 2000
        $('#_process').spin('stop')

      error: (data) ->
        $('#_status > div').removeClass('alert-success').addClass('alert-error')
        $('#_status > div').html( data.responseText )
        $('#_status').fadeIn()
        fade = () -> $('#_status').fadeOut('slow')
        setTimeout fade, 2000
        $('#_process').spin('stop')

      complete: () -> $('#_process').spin('stop')

footer.scala.html

 <div id="_status">
    <div class="alert alert-error"></div>
 </div>
 <div class="input-append">
    <form id="_form" action="@routes.ApplicationController.simpleSubscription">
       <input type="text" name="emailAddress" placeholder="Your Email" />
       <input id="_process" class="btn" type="submit" value="Subscribe" />
    </form>
    <div id="_spin"></div>
  </div> <!-- /input-append -->

spin（）函数来自https://github.com/pshizzle/spin.coffee

Answer 1

AJAX是方式™

//footer.scala.html
<div id="footer">
  <div class="input-append">
    <form id="_form" action="@routes.ApplicationController.saveSubscription">
      <input type="text" name="emailAddress" placeholder="Your Email" />
      <input id="_process" class="btn" type="submit" value="Subscribe" />
      <img id="spinner" src="/assets/img/loader.gif" alt="loading..." />
    </form>
  </div>
</div>

<div id="status">
  <div class="alert alert-error"></div>
</div>
<style type="text/css">
  #spinner, #status { display: none; }
</style>

//ApplicationController.java
public class ApplicationController extends Controller {
  public static Result saveSubscription() {
    // save subscription
    ...
    // pseudo code
    if(success) 
      Ok( i18n("subscription success").toJson() );
    else
      Conflict( i18n("subscription fail").toJson() );
  }
}

//main.coffee
jQuery ->
  $.ajaxSetup
    type:     "POST"
    cache:    false
    dataType: "json"

  # prevent form submit on keypress
  $('form').find('input').keypress (e) -> e.preventDefault() if(e.which == 13)

  jParse = (data) -> 
    try jQuery.parseJSON(data)
    catch e
      data

  jText = (data) -> jParse(data.responseText)

  toSuccess = (msg) -> 
    $('#status > div').removeClass('alert-error').addClass('alert-success')
    $('#status > div').html( jParse(msg) )
    $('#status').fadeIn()

  toFail = (data) -> 
    $('#status > div').html( jText(data) )
    $('#status').fadeIn()

//subscribe.coffee
jQuery ->
  $('#_process').click (e) ->
    e.preventDefault()

    isValid = $('#_form').validate().form() // assumes jQuery validation plugin
    if isValid
      $('#spinner').show()
      $.ajax
        data: $('#_form').serialize()
        success: (msg) ->
          toSuccess(msg)
          fade = () -> $('#status').fadeOut('slow')
          setTimeout fade, 2000

        error: (data) -> toFail(data)

        complete: () -> $('#spinner').hide()

Answer 2

如何准备在隐藏字段中使用重定向地址？

footer

@(returnPath: String)
<form action="@routes.ApplicationController.saveSubscription()" method="post">
    ...
    <input type="hidden" name="returnPath" value="@returnPath" />
</form>

page1

@main("Page 1") {
    ...
    <!-- it's important to use toString at the end -->
    @footer(routes.ApplicationController.page1.toString)
}

甚至更好：从当前path

中提供request()

@main("Page 1") {
    ...
    @footer(request.path)
}

controller

public static Result saveSubscription() {
    ...
    flash("success", "success message");
    return redirect(form().bindFromRequest().get("returnPath"));
}

顺便说一句：也许使用AJAX表单会更容易和更好？在这种情况下，您可以避免冗余重新加载（并查找对象并一次又一次地渲染整个模板等）

使用2.0模板重用页脚模板的正确方法

2 个答案: