Question

这是工作的PHP代码

<?php
$str = '<users>
<user id="1" value1="afaaf" value2="racad" value3="xarcd">User1</user>
<user id="2" value1="fsvgvdsg" value2="wdafsc" value3="aefvbdfg">User2</user>
<user id="3" value1="chthb" value2="rtvfascf" value3="xasedfvg">User3</user>
</users>';
$out = '';
if(preg_match_all('|<user id="(.*)" value1="(.*)" value2="(.*)" value3="(.*)">(.*)</user>|',$str,$matches))
{
    for($i=0;$i<count($matches[1]);$i++)
    $out .= $matches[1][$i].'|'.$matches[2][$i].'|'.$matches[3][$i].'|'.$matches[4][$i].'|'.$matches[5][$i]."\n";

    echo $out;
}
 ?>

这就是我得到的

1|afaaf|racad|xarcd|User1
2|fsvgvdsg|wdafsc|aefvbdfg|User2
3|chthb|rtvfascf|xasedfvg|User3

C＃代码

    string patt = "<user id=\"(.*)\" value1=\"(.*)\" value2=\"(.*)\" value3=\"(.*)\">(.*)</user>";
    string str = "<users><user id=\"1\" value1=\"afaaf\" value2=\"racad\" value3=\"xarcd\">User1</user><user id=\"2\" value1=\"fsvgvdsg\" value2=\"wdafsc\" value3=\"aefvbdfg\">User2</user><user id=\"3\" value1=\"chthb\" value2=\"rtvfascf\" value3=\"xasedfvg\">User3</user></users>";
    MatchCollection mc;
    Regex r = new Regex(patt);
    mc = r.Matches(str);

    for (int i = 0; i < mc.Count; i++)
        textBox1.Text += mc[i].Value + "\r\n";

我得到了

<user id=\"1\" value1=\"afaaf\" value2=\"racad\" value3=\"xarcd\">User1</user><user id=\"2\" value1=\"fsvgvdsg\" value2=\"wdafsc\" value3=\"aefvbdfg\">User2</user><user id=\"3\" value1=\"chthb\" value2=\"rtvfascf\" value3=\"xasedfvg\">User3</user>\r\n

你可以看到我从c＃代码得到的字符串甚至不接近我的php结果。

如何从我的PHP代码获得结果？

希望你能理解我的问题在这里。

由于

Answer 1

试试这个：

change (.*) to (.*?) in you RegEx pattern

并将您的代码段修改为：

for (int i = 0; i < mc.Count; i++)
    textBox1.Text += mc[i].Groups[1].Value + mc[i].Groups[2].Value + mc[i].Groups[3].Value + + mc[i].Groups[4].Value + mc[i].Groups[5].Value + "\r\n";

Answer 2

使用正则表达式的另一种方法可能是使用LinqToXml，这是一个例子。

方式

const string xmlString = "<users><user id='1' value1='afaaf' value2='racad' value3='xarcd'>User1</user><user id='2' value1='fsvgvdsg' value2='wdafsc' value3='aefvbdfg'>User2</user><user id='3' value1='chthb' value2='rtvfascf' value3='xasedfvg'>User3</user></users>"; var doc = XDocument.Parse(xmlString); // defensive coding should be applied, this example // omits it for simplicity // the u will be a list of type User (3 items in this example) var u = doc.Descendants("user").Select(user => new User { Id = int.Parse(user.Attribute("id").Value), Value1 = user.Attribute("value1").Value, Value2 = user.Attribute("value2").Value, Value3 = user.Attribute("value3").Value });

<强>模型

public class User { public int Id { get; set; } public string Value1 { get; set; } public string Value2 { get; set; } public string Value3 { get; set; } public override string ToString() { return string.Format("{0}|{1}|{2}|{3}", Id, Value1, Value2, Value3); } }

Answer 3

试试这个。（ TESTED ）

string patt = "<user id=\"(?<id>.*?)\" value1=\"(?<value1>.*?)\" value2=\"(?<value2>.*?)\" value3=\"(?<value3>.*?)\">(?<name>.*?)</user>";
        string str = "<users><user id=\"1\" value1=\"afaaf\" value2=\"racad\" value3=\"xarcd\">User1</user><user id=\"2\" value1=\"fsvgvdsg\" value2=\"wdafsc\" value3=\"aefvbdfg\">User2</user><user id=\"3\" value1=\"chthb\" value2=\"rtvfascf\" value3=\"xasedfvg\">User3</user></users>";
        MatchCollection mc;
        Regex r = new Regex(patt);
        mc = r.Matches(str);

        foreach (Match item in mc)
        {
            string id = item.Groups["id"].Value;
            string value1 = item.Groups["value1"].Value;
            string value2 = item.Groups["value2"].Value;
            string value3 = item.Groups["value3"].Value;
            string name = item.Groups["name"].Value;

            textBox1.Text += id + "|" + value1 + "|" + value2 + "|" + value3 + "|" + name + "\r\n";
        }

C＃正则表达式匹配（相当于php_match_all）

3 个答案: