感谢您阅读此问题。
基本上我正在尝试执行以下代码:
将向用户显示此类详细信息的列表
终端视图:
Please select the department you want to add participant:
1. Admin
2. HR
3. Normal
4. Back to Main Menu
Selection: 3
normal's Department
UserID: 85 [ Name: Andrew, Department: normal ]
UserID: 86 [ Name: Jacky, Department: normal ]
UserID: 90 [ Name: Baoky, Department: normal ]
Current Selected Participant :
Usage:
Type exit to return to main menu
Type remove userid to remove participant
Type add userid to add participant
Selection:
问题是: 我希望能够让用户添加尽可能多的参与者,直到他决定“退出”到主菜单,但我如何将其存储在字符串参与者中。
如何检测用户输入是'删除用户ID' 或'添加用户ID'然后获取用户ID
例如添加86 然后他加了90
然后他决定删除90字符串如何与它保持同步
以下是我的代码:
do
{
cout << "Current Selected Participant : " << participant << endl;
cout << "" << endl;
do
{
if(counter>0)
{
//so it wont print twice
cout << "Usage: " << endl;
cout << "Type exit to return to main menu" << endl;
cout << "Type remove userid to remove participant" << endl;
cout << "Type add userid to add participant" << endl;
cout << "" << endl;
cout << "Selection: ";
}
getline(cin,buffer);
counter++;
}while(buffer=="");
if(buffer.find("remove"))
{
str2 = "remove ";
buffer.replace(buffer.find(str2),str2.length(),"");
if(participant.find(buffer))
{
//see if buffer is in participant list
buffer = buffer + ",";
participant.replace(participant.find(buffer),buffer.length(),"");
}
else
{
cout << "There no participant " << buffer << " in the list " << endl;
}
}//buffer find remove keyword
if(buffer=="exit")
{
done=true;
}
else
{
sendToServer = "check_account#"+buffer;
write (clientFd, sendToServer.c_str(), strlen (sendToServer.c_str()) + 1);
//see if server return found or not found
readFromServer = readServer (clientFd);
if(readFromServer=="found")
{
//add to participant list
participant += buffer;
participant += ",";
}
}//end if not exit
}while(done!=true);
有些用户建议我存储在字符串集中,如何存储在字符串集中,以及如何使终端能够识别选择中的“删除”和“添加”等关键字
然后获取用空格分隔的用户ID。
接下来是如何删除我是否存储在字符串集中以及如何在其中推送新值。
答案 0 :(得分:1)
不要将其存储在字符串中。将其存储在一个允许轻松插入和移除的集合中,如std::set<int>
。完成此过程后,您可以将该集转换为您认为需要的任何表示形式。
这是一个非常简单的例子(没有检查它是否编译并运行;这是留给读者的练习!)
void handle_command(const std::string& command, std::set<std::string>& userids)
{
if (command.substr(0, 4) == "add ")
{
std::string uid = command.substr(4);
if (userids.find(uid) == userids.end())
userids.insert(uid);
else
std::cout << "Uid already added" << std::endl;
return;
}
else
throw std::exception("Unsupported command, etc");
}