Question

如何在PowerShell中创建并抛出新的异常？

我想针对特定错误做不同的事情。

Answer 1

要调用特定的异常，例如FileNotFoundException，请使用此格式

if (-not (Test-Path $file)) 
{
    throw [System.IO.FileNotFoundException] "$file not found."
}

要抛出一般异常，请使用throw命令后跟一个字符串。

throw "Error trying to do a task"

在catch中使用时，您可以提供有关触发错误的内容的其他信息

Answer 2

您可以通过扩展 Exception 类来抛出您自己的自定义错误。

class CustomException : Exception {
    [string] $additionalData

    CustomException($Message, $additionalData) : base($Message) {
        $this.additionalData = $additionalData
    }
}

try {
    throw [CustomException]::new('Error message', 'Extra data')
} catch [CustomException] {
    # NOTE: To access your custom exception you must use $_.Exception
    Write-Output $_.Exception.additionalData

    # This will produce the error message: Didn't catch it the second time
    throw [CustomException]::new("Didn't catch it the second time", 'Extra data')
}

创建并抛出新的异常

2 个答案: