$rowgp="select name,m3,dpsd,phc,jtk from 2sem3 where rno='$rno'";
$resultrow=mysql_query($rowgp);
while($row=mysql_fetch_array($resultrow)){
echo $row['m3'] ." ". $row['oops'];
$one = $row['m3'];
$two = $row['oops']
}
在上面的代码中,变量$one
包含a到d的字符(这些是字段m3
中存在的字符)。如果char为'a',则应将其设为1;如果'b'则为2(c = 3,d = 4,依此类推)。如果不使用if或switch语句,我怎么能这样做?
答案 0 :(得分:6)
$chars = range('a', 'z');
$nums = array_flip($chars);
echo $nums[$one] + 1;
答案 1 :(得分:3)
可以使用ord()
echo (ord($row['m3']) - ord('a') + 1);
答案 2 :(得分:1)
$lookup = array('a'=>1, 'b'=>2, 'c'=>3, 'd'=>4);
$rowgp="select name,m3,dpsd,phc,jtk from 2sem3 where rno='$rno'";
$resultrow=mysql_query($rowgp);
while($row=mysql_fetch_array($resultrow)){
echo $row['m3'] ." ". $row['oops'];
$one = $lookup[$row['m3']];
$two = $row['oops']
}